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3 years ago

Guys I need help with my homework please !!!!

Physics

1 answer:

Sergio [31]3 years ago

6 0

Answer:

(a) To draw water from a well we have to pull at the rope.

(b) A charged body attracts an uncharged body towards it.

(d) The north pole of a magnet repels the north pole of another magnet.

Explanation:

Just trust me

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The heater element of a particular 120-V toaster is a 8.9-m length of nichrome wire, whose diameter is 0.86 mm. The resistivity

AleksAgata [21]

Answer:

Power, P = 722.96 watts

Explanation:

It is given that,

Voltage, V = 120 V

Length of nichrome wire, l = 8.9 m

Diameter of wire, d = 0.86 mm

Radius of wire, r = 0.43 mm = 0.00043 m

Resistivity of wire, $\rho=1.3\times 10^{-6}\ \Omega-m$

We need to find the power drawn by this heater. Power is given by :

$P=\dfrac{V^2}{R}$

And, $R=\rho\dfrac{l}{A}$

$P=\dfrac{V^2\times A}{\rho\times l}$

$P=\dfrac{120^2\times \pi (0.00043)^2}{1.3\times 10^{-6}\times 8.9}$

P = 722.96 watts

So, the power drawn by this heater element is 722.96 watts. Hence, this is the required solution.

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3 years ago

A 50-cm wire placed in an east-west direction is moved horizontally to the north with a speed of 2.0 m/s. the horizontal compone

Strike441 [17]

When a wire is moved inside uniform magnetic field then its free electrons will experience magnetic force on it due to which wire will have potential difference at its ends.

Now here we will have magnetic field due to earth and wire is moving in this constant field so induced emf is given by formula

$EMF = v.(B x L)$

given that

$B = 25\mu Tj - 50\mu Tk$

$v = 2 m/s j$

$L = 0.50 m (-i)$

now by using the above formula we will have

$EMF = 2(j) .(25\mu j - 50\mu k) x (-0.50 i)$

$EMF = 2(j) .(12.5\mu k + 25\mu j)$

$EMF = 50 \mu Volts$

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