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Bumek [7]
3 years ago
9

What is the radius of a bobsled turn banked at 75.0^\circ75.0 ​∘ ​​ and taken at 30.0 m/s, assuming it is ideally banked?

Physics
1 answer:
Contact [7]3 years ago
4 0

Banking angle is the angle between the normal horizontal path (N) and the curved banked path. The angle of banking of a curved path is defined as the angle through which the outer edge of the road is raised over the inner edge.

It is calculated as:

tan\theta = \frac{v^2}{rg}

Here,

v = Linear velocity of object

r = Radius of the curved path

a_c = Acceleration due to gravity

Rewriting the equation to solve for the radius we have that

r=\frac{v^2}{gtan\theta}

r = \frac{30}{(9.8)(tan 75\°)}

r = 24.6m

Therefore the radius of a bobsled turn banked at 75° taken at 30m/s is 24.6m

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