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2 years ago

A student drops a ball from the top of a tall building; it takes 2.9 s for the ball to reach the ground.

Physics

1 answer:

AlexFokin [52]2 years ago

4 0

Initial velocity (u) = 0 m/s
Time taken (t) = 2.9s
Acceleration due to gravity (g) = + 10 m/s² [Down]

<h2><u>To calculate</u>,</h2>

Final velocity (v)
Height (h)

<h2><u>Solution</u><u>,</u></h2>

→ v = u + gt

→ v = 0 + 10(2.9)

→ v = 29 m/s $\qquad$ … ( Ans )

And,

→ h = ut + ½gt²

→ h = 0(2.9) + ½ × 10 × (2.9)²

→ h = 5 × 8.41

→ h = 42.05 m $\qquad$ … ( Ans )

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