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BlackZzzverrR [31]
3 years ago
8

Which one of the following is a free radical?

Chemistry
1 answer:
My name is Ann [436]3 years ago
5 0

Answer:

where are the following

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Divers who go to great depths in the ocean experience large differences in pressure between the surface and their final destinat
baherus [9]

Since solubility decreases rapidly as the diver returns to the surface, the risk of having “the bends” is greater as the diver returns to the surface.

The solubility of a gas refers to the amount of the gas that dissolves in a liquid. Solubility of a gas is dependent on pressure. The greater the pressure, the higher the solubility of the gas and vice versa.

Pressure increases with depth as a diver moves down the sea. More pressure is exerted, the deeper the diver goes. This means that solubility of nitrogen in blood increases at a greater depth.

As the diver returns to the surface, the pressure decreases rapidly and the solubility of nitrogen also decreases suddenly making the risk of “the bends” to be greater as the diver returns to the surface.

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8 0
3 years ago
Which of the following is an oxidation-reduction reaction?
Hatshy [7]

B. The chemical reaction that represents oxidation - reduction reaction is CaCO3(s) → CaO(s) + CO2(g).

<h3>Oxidation reduction reaction</h3>

In oxidation reduction reaction, the oxidizing agent is reduced while reducing agent is oxidized.

<h3>In the chemical equation below;</h3>

CaCO3(s) → CaO(s) + CO2(g)

Calcium (ca) is oxidized calcium (II) ion while the carbon (IV) oxide is reduced carbon (IV) oxide.

Thus, the chemical reaction that represents oxidation - reduction reaction is CaCO3(s) → CaO(s) + CO2(g).

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8 0
2 years ago
General Information. A brief introduction about the caffeine.​
viva [34]

Answer: A central nervous system stimulant

Explanation: arguably the most frequently ingested pharmacologically active substance in the world.

3 0
3 years ago
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Draw structures from the following names, and determine which compounds are optically active:(b) 3-chloro-2,2,5-trimethylhexane
inn [45]

The given compound 3-chloro-2,2,5-trimethylhexane is an optically active compound .

Because this compound does not have plane of symmetry (POS) and center  of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .

It has  chiral center.

Here the chiral carbon has 4 distinct groups such as : chlorine , hydrogen , 2-methylpropyl , tertbutyl .

<h3>What is di-symmetry?</h3>

Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .

<h3>Chiral center :</h3>

Have Sp3 hybridized center (4sigma bond ) .

4 distinct group  is attached to the chiral atom. form non -superimposable mirror image .

<h3>What is optical isomerism ?</h3>

Same molecular formula and same structural formula . also have same physical and chemical properties .

They differ in their behavior towards plane polarized light (ppl) .

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7 0
2 years ago
What is the vapor pressure (in mm Hg) of a solution of 17.5 g of glucose (C6H12O6) in 82.0 g of methanol (CH3OH) at 27∘C? The va
vichka [17]

Answer:

134.8 mmHg is the vapor pressure for solution

Explanation:

We must apply the colligative property of lowering vapor pressure, which formula is: P° - P' = P° . Xm

P° → Vapor pressure of pure solvent

P' → Vapor pressure of solution

Xm → Mole fraction for solute

Let's determine the moles of solute and solvent

17.5 g . 1 mol/180 g = 0.0972 moles

82 g . 1mol / 32 g = 2.56 moles

Total moles → moles of solute + moles of solvent → 2.56 + 0.0972 = 2.6572 moles

Xm → moles of solute / total moles = 0.0972 / 2.6572 = 0.0365

We replace the data in the formula

140 mmHg - P' = 140 mmHg . 0.0365

P' = - (140 mmHg . 0.0365 - 140mmHg)

P' = 134.8 mmHg

5 0
3 years ago
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