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Reika [66]
3 years ago
15

Explain how the electrical model for the control of cellvolume

Chemistry
1 answer:
AlexFokin [52]3 years ago
6 0

Answer:

Control of Cell Volume and Membrane Potential Basic

Basic problem

• The cell is full of components like Proteins, ions, fats, etc.

• Ordinarily, these would cause huge osmotic pressures, sucking water into the cell.

• The cell membrane has no structural strength, and the cell would burst.

Basic solution to the problem above

• Cells carefully regulate their intracellular ionic concentrations in order, to ensure that no osmotic pressures arise

• Consequently, the major ions Na+, K+, Cl- and Ca2+ in the cell have different concentrations in the extracellular and intracellular environments.

• And thus a voltage difference arises across the cell membrane.

Essentially two different kinds of cells: excitable and nonexcitable.

• All cells have a resting membrane potential, but only excitable cells modulate it actively.

Explanation:

In the case where there is a poisoning of the Na-K exchange pump.

Inhibition kicks off.

The pump requires binding by Na+ , K+ and ATP for its operation. Therefore , if the concentration of any of these substances is too low, the pump does not function.

When the temperature is reduced. During oxygen lack. Metabolic poisoning thus prevents the formation of ATP.

Potential buildup in the Na+ ion will be used by many different processes e.g cotransporter, neuron signalling etc.

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How many electrons in each orbit?
sveticcg [70]
In 1st orbit 2
2nd 8
3rd 10
f orbital has 16
4 0
3 years ago
The mass of 0.10 mole of methane
saveliy_v [14]

Answer:

A methane molecule is made from one carbon atom and four hydrogen atoms. Carbon has a mass of 12.011 u and hydrogen has a mass of 1.008 u. This means that the mass of one methane molecule is 12.011 u + (4 × 1.008u), or 16.043 u. This means that one mole of methane has a mass of 16.043 grams.

メタン分子は、1つの炭素原子と4つの水素原子から作られています。炭素の質量は12.011uで、水素の質量は1.008uです。これは、1つのメタン分子の質量が12.011 u +(4×1.008u)、つまり16.043uであることを意味します。これは、1モルのメタンの質量が16.043グラムであることを意味します。^>^

5 0
3 years ago
At constant pressure, which of these systems do work on the surroundings? A ( s ) + B ( s ) ⟶ C ( g ) A(s)+B(s)⟶C(g) 2 A ( g ) +
Tju [1.3M]

Correct question:

At constant pressure, which of these systems do work on the surroundings?

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

(c) A ( g ) + B ( g ) ⟶ C ( g )

(d) 2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

Answer:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

Explanation:

Work done by a system on the surroundings at a constant pressure is given as;

W = -PΔV

Where;

ΔV is gas expansion, that is final volume of the gas minus initial volume of the gas must be greater than zero.

Part (a)

A ( s ) + B ( s ) ⟶ C ( g )

ΔV = 1 - (0) = 1 (expansion)

Part (b)

2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

ΔV = 5 - ( 2+ 2) = 1 (expansion)

Part (c)

A ( g ) + B ( g ) ⟶ C ( g )

ΔV = 1 - ( 1 + 1) = -1 (compression)

Part (d)

2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

ΔV = 3 - ( 4) = -1 (compression)

Thus, systems where there is gas expansion are in part (a) and part (b). The correct answers are:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

4 0
2 years ago
Can someone please help? We're studying astronomy and I have no idea what to name it. I was never good with names. ‍♀️
almond37 [142]
I do not understand your question, what is the question, name what??
5 0
3 years ago
C2h4 3 o2 2 co2 2 h2o
Marat540 [252]
Use the question marck Moles of CO2
The the giving = 0.624 mol O2
Find the CF faction = 1 mole=  32.00 of O2

O= 2x16.00= 32.00amu ( writte this in the cf fraction)
SET UP THE CHART
Always start with the giving

0.624 mol O2    /  1mol of CO2
___________  / _____________ = Cancel the queal ( O2)
                       / 32.00c O2
                      /
                     /
Multiply the top and divide by the bottom 
0.624 mol CO x 1mol CO2 = 0.624 divide by 32.00 O2 =0.0195
You should look at the giving number ( how many num u gor ever there) 
Ur answer should have the same # as ur givin so 
= 0.0195 
= .0195 mol of CO2
3 0
3 years ago
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