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Reika [66]
4 years ago
15

Explain how the electrical model for the control of cellvolume

Chemistry
1 answer:
AlexFokin [52]4 years ago
6 0

Answer:

Control of Cell Volume and Membrane Potential Basic

Basic problem

• The cell is full of components like Proteins, ions, fats, etc.

• Ordinarily, these would cause huge osmotic pressures, sucking water into the cell.

• The cell membrane has no structural strength, and the cell would burst.

Basic solution to the problem above

• Cells carefully regulate their intracellular ionic concentrations in order, to ensure that no osmotic pressures arise

• Consequently, the major ions Na+, K+, Cl- and Ca2+ in the cell have different concentrations in the extracellular and intracellular environments.

• And thus a voltage difference arises across the cell membrane.

Essentially two different kinds of cells: excitable and nonexcitable.

• All cells have a resting membrane potential, but only excitable cells modulate it actively.

Explanation:

In the case where there is a poisoning of the Na-K exchange pump.

Inhibition kicks off.

The pump requires binding by Na+ , K+ and ATP for its operation. Therefore , if the concentration of any of these substances is too low, the pump does not function.

When the temperature is reduced. During oxygen lack. Metabolic poisoning thus prevents the formation of ATP.

Potential buildup in the Na+ ion will be used by many different processes e.g cotransporter, neuron signalling etc.

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A 0.8715 g sample of sorbic acid, a compound first obtained from the berries of a certain ash tree, is burned completely in oxyg
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<h3><u>Answer</u>;</h3>

C3H4O

<h3><u>Explanation;</u></h3>

Empirical formula is the simplest formula of a compound;

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Mass of CO2 produced = 2.053 g

Mass of carbon in original sample = 12.01/44.01 × 2.053

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Thus; original sample contained 0.5603g C and 0.0622g H. The balance of the sample was O  

Mass of O = 0.8715 - (0.5603 + 0.0622) = 0.249g  

The mole ratio of C:H:O  will be;

Moles C = 0.5603/12 = 0.0467  

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C:H:O = 0.0467:0.0622:0.01556  

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C:H:O = 3:4:1  

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