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ValentinkaMS [17]
3 years ago
8

What grade percentage is developing, proficient, exceeding, and emerging?​

Chemistry
2 answers:
user100 [1]3 years ago
5 0

Answer:

Grade A is the best percentage that is developing, proficient, exceeding, and emerging

laila [671]3 years ago
3 0
The answer will be 60% - 80%.
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When iron metal reacts with oxygen, the reaction can form Fe2O3. Write a balanced chemical equation for this reaction, and find
I am Lyosha [343]
<h3>Answer:</h3>

Balanced equation: 4Fe + 3O₂ → 2Fe₂O₃

Moles of oxygen gas = 9 moles

<h3>Explanation:</h3>

To answer the question;

  • We first write the balanced equation between iron metal and Oxygen
  • The balanced equation is given as;

4Fe + 3O₂ → 2Fe₂O₃

  • We are given 6 moles of Fe₂O₃

We are required to determine the number of moles of oxygen needed to form 6 moles of Fe₂O₃.

  • From the equation, 3 moles of oxygen gas reacts to produce 2 moles of Fe₂O₃
  • This means, the mole ratio of O₂ to Fe₂O₃ is 3 : 2

Therefore; Moles of O₂ = Moles of Fe₂O₃ × 3/2

Hence, moles of oxygen = 6 moles × 3/2

                                         = 9 moles

Thus, Moles of Oxygen needed is 9 moles

6 0
3 years ago
The natural process where the sun's energy is trapped by the atmosphere to make the Earth warm enough for life is known as
Juliette [100K]
The greenhouse effect captures the sun's energy and keeps the earth warm.
5 0
3 years ago
Although incineration can break down harmful chemicals, the byproduct is hazardous.
cestrela7 [59]
A, true is the answer and cluke u help me please
6 0
3 years ago
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Can someone please help mee finish this?
zvonat [6]

Answer:

1.Physical. People measure water by themselves.

2.Physical. People chop wood.

Explanation:

(this is all I can answer for you. you have to explain it by yourself tho.)

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4 0
4 years ago
In the first 22.0 s of this reaction, the concentration of HBr dropped from 0.590 M to 0.465 M . Calculate the average rate of t
jolli1 [7]

Answer:

The average rate is 2.84 X 10⁻³ Ms⁻¹

Explanation:

Average rate = -0.5*Δ[HBr]/Δt

given;

[HBr]₁ = 0.590 M

[HBr]₂ = 0.465 M

Δ[HBr] = [HBr]₂  - [HBr]₁ = 0.465 M - 0.590 M = -0.125 M

Δt Change in time = 22.0 s

Average rate = -0.5*Δ[HBr]/Δt

Average rate = - 0.5(-0.125)/22

Average rate = 0.00284 Ms⁻¹ = 2.84 X 10⁻³ Ms⁻¹

Therefore, the average rate is 2.84 X 10⁻³ Ms⁻¹

8 0
3 years ago
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