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3 years ago

A coyote and an oak tree both have DNA?

Chemistry

2 answers:

denis-greek [22]3 years ago

7 0

Answer:

true, they both have different types of DNA.

PtichkaEL [24]3 years ago

6 0

Answer:

Um yes... they have different DNA's.. ;-;

Explanation:

You might be interested in

If it takes 22974 J to heat 96.5 g of a substance from 13.46°C to 73.86 °C, what is the specific heat of the substance?

yulyashka [42]

The specific heat capacity, C, of the substance is 3.94 $\frac{J}{g-^oC}$ . To raise one gram of a substance by one degree Celsius, a specific amount of heat must be absorbed. This is called the specific heat of the substance. The higher the specific heat of a substance, the more energy is needed to increase its temperature and vice versa.

<u>Further Explanation: </u>

The specific heat capacity, C, of a substance is related to the amount of substance and the temperature change using the following equation

$q \ = \ mC(T_{f}-T_{i})$

where

q = amount of heat absorbed (usually in J)

m = amount of substance (in g)

C = specific heat capacity (in $\frac{J}{g-^oC}$ )

T(f) = final temperature

T(i) = initial temperature.

To answer the problem, we sort the given information:

q = 22974 J (5 significan figures)

m = 96.5 g (3 significant figures)

C = ?

T(f) = 73.86 °C (4 significant figures)

T(i) = 13.46 °C (4 significant figures)

Then, to find C, rearrange the equation:

$C \ = \frac{q}{m(T_{f} \ - \ T_{i})}$

Plug in the values to the equation above to get the value of C.

$C \ = \ \frac{22974 \ J}{96.5 \ g \ (73.86 \ \ -13.46 \°C)} \\C \ = \ \frac{22974 \ J}{96.5 \ g \ (60.4\°C)} \\C \ = \ \frac{22974 \ J}{5828.6 \ g -\°C} \\C \ = \ 3.941598 \ \frac{J}{g -\°C} \\$

Since the least number of significant figures in the given is 3, then the final answer must have 3 significant figures, too. Therefore,

$\boxed {C = 3.94 \ \frac{J}{ g -\°C}}$

<u></u>

<u>Learn More: </u>

1. Learn more about heat capacity brainly.com/question/8828503

2. Learn more about calorimetry brainly.com/question/8168263

3. Learn more about heat of reaction brainly.com/question/10122365

<u>Keywords:</u> heat capacity, specific heat, calorimetry

4 0

3 years ago

What is a orgasm that kills and eats other orgasms for food called?

dalvyx [7]

The answer is predator

5 0

3 years ago

Read 2 more answers

What is the Hazard of Silicon?

hoa [83]

Answer:

Silicon dust has little adverse affect on lungs and does not appear to produce significant organic disease or toxic effects when exposures are kept beneath exposure limits. Silicon may cause chronic respiratory effects. Crystalline silica (silicon dioxide) is a potent respiratory hazard.

6 0

3 years ago

11. You have 700 grams of AgO. How many moles are present?

solniwko [45]

<h2>Answer:</h2>

5.65moles

<h2>Explanations:</h2>

The formula for calculating the number of moles the compound contain is given as:

$moles=\frac{Mass}{Molar\text{ mass}}$

Given the following parameters

Mass of Ag = 700grams

Determine the molar mass of AgO

Molar mass = 107.87 + 16

Molar mass = 123.87g/mol

Determine the moles of AgO

$\begin{gathered} moles=\frac{700}{123.87} \\ moles\text{ of AgO}=5.65moles \end{gathered}$

Hence the moles of AgO present is 5.65moles

7 0

1 year ago

Use the atomic mass of indium to calculate the relative abundance of indium-113.

ASHA 777 [7]

The relative abundance of indium-113 is 4%.

The isotopes are species of the same element having the same atomic number but a different mass number.

The elements occurring in nature exist as multiple isotopes.

When we take into account the existence of these isotopes and their relative abundance (percent), the average atomic mass of that element can be computed, which is given by the following formula,

Average atomic Mass= (%age of isotope 1) x (Mass of isotope 1) + (%age of isotope 2) x (Mass of isotope 2)/100

Indium exists in the form of Indium-113 and Indium-115.

The mass of Indium-113 is 112.90 u.

The mass of Indium-115 is 114.90 u.

The average atomic mass of Indium is 114.82 u.

Let the %age of isotope 1(Indium-113) be X.

Then, the %age of isotope 2(Indium-115) would be 100-X.

Applying the values in the formula,

Average atomic mass = 112.90X+114.90(100-X)

114.82 = 112.90X+114.90(100-X)

On solving the above equation, the value of X comes out to be 4%.

Thus, the relative abundance/%age abundance of Indium-113 is 4%.

To know more about "Average Atomic Mass", refer to the following link:

brainly.com/question/13753702?referrer=searchResults

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7 0

1 year ago