Where is thermal equilibrium achieved between two objects

Alona [7]

Answer:

Potassium iodide increases the decomposition rate of hydrogen peroxide.

Explanation:

Potassium iodide increases the decomposition rate of hydrogen peroxide because potassium iodide act as a catalyst. A catalyst speed up the process of chemical reaction without reacting with the molecules present in reaction. If the potassium iodide is not present as a catalyst for the decomposition of hydrogen peroxide then the decomposition of hydrogen peroxide takes too much time because the catalyst is absent that speed up the reaction.

5 0

3 years ago

The accepted value for the density of iron is 7.9 g/mL. Four student groups examine the density of iron in the lab. Which of the

nalin [4]

For 5.43 g/mL and 5.44 g/mL = 0.01 the least diff and most precise.

First of all, precision is determined by the difference in the two obtained values. If the difference between the two values obtained is less, then precision is more. If the difference between the two values obtained is more, then precision is less.

For 5.43 g/mL and 5.44 g/mL , we can see that the difference between these two data is 0.01

For 7.98 g/mL and 7.91 g/mL , we can see that the difference between these two data is 0.07

For 7.65 g/mL and 7.64 g/mL , we can see that the difference between these two data is 0.01

For 7.06 g/mL and 7.03 g/mL , we can see that the difference between these two data is 0.03

As we can see that, the most difference between the data is 0.07 between 7.65 g/mL and 7.64 g/mL and thus, they are least precise.

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3 0

2 years ago

List the five major pollutants in the United States

lawyer [7]

Fine particles, ground level ozone, sulfur dioxide, nitrogen dioxide, lead

6 0

4 years ago

How many grams of Cl, will be produced by the electrolysis of 23.4 g NaCl?

VLD [36.1K]

Answer:

Explanation:

You know that

2

Na

(

s

)

+

Cl

2

(

g

)

→

2

NaCl

(

s

)

and that the reaction produced

234 g

of sodium chloride. Convert this to moles by using the compound's molar mass

234

g

⋅

1 mole NaCl

58.44

g

=

4.004 moles NaCl

Now, you know that the sample of sodium metal reacted completely, which implies that it was completely consumed by the reaction.

In other words, you don't have to worry about the sample of chlorine gas because the fact that sample of sodium metal was completely consumed lets you know that the chlorine gas is not a limiting reagent.

This means that the reaction consumed

4.004

moles NaCl

⋅

2 moles Na

2

moles NaCl

=

4.004 moles Na

Convert this to grams by using the element's molar mass

4.004

moles Na

⋅

22.99 g

1

mole Na

=

92.1 g

−−−−−

The answer is rounded to three sig figs.

SIDE NOTE You can show that chlorine gas is not the limiting reagent by calculating the number of moles present in the sample

0.142

kg

⋅

1 mole Cl

2

35.453

kg

=

4.005 moles Cl

2

In order to produce

4.004

moles of sodium chloride, you only need

4.004

moles NaCl

⋅

1 mole Cl

2

moles NaCl

=

2.002 moles Cl

2

Since you have more chlorine gas than you need, chlorine is in excess.vExplanation:

You know that

2

Na

(

s

)

+

Cl

2

(

g

)

→

2

NaCl

(

s

)

and that the reaction produced

234 g

of sodium chloride. Convert this to moles by using the compound's molar mass

234

g

⋅

1 mole NaCl

58.44

g

=

4.004 moles NaCl

Now, you know that the sample of sodium metal reacted completely, which implies that it was completely consumed by the reaction.

In other words, you don't have to worry about the sample of chlorine gas because the fact that sample of sodium metal was completely consumed lets you know that the chlorine gas is not a limiting reagent.

This means that the reaction consumed

4.004

moles NaCl

⋅

2 moles Na

2

moles NaCl

=

4.004 moles Na

Convert this to grams by using the element's molar mass

4.004

moles Na

⋅

22.99 g

1

mole Na

=

92.1 g

−−−−−

The answer is rounded to three sig figs.

SIDE NOTE You can show that chlorine gas is not the limiting reagent by calculating the number of moles present in the sample

0.142

kg

⋅

1 mole Cl

2

35.453

kg

=

4.005 moles Cl

2

In order to produce

4.004

moles of sodium chloride, you only need

4.004

moles NaCl

⋅

1 mole Cl

2

moles NaCl

=

2.002 moles Cl

2

Since you have more chlorine gas than you need, chlorine is in excess.

Explanation:

8 0

3 years ago

What conditions favor the formation of ionic compounds from elements? both atoms must be non metals. you must have a metal and a

astraxan [27]

You must have a metal and a non-metal

6 0

4 years ago