All categories

1 year ago

The diagram shows the movement of particles from one end of the container to the opposite end of the container.

1 answer:

3 0

The event which is most likely occurring in this scenario is effusion because there is a movement of a gas through a small opening into a larger volume and is denoted as option C.

<h3>What is Effusion?</h3>

This is referred to as the process in which a gas or a substance escapes from a container through a hole of diameter which is usually smaller.

The type of event which is most likely occurring is effusion because of the presence of the small holes in which the balls are made to pass through the center which is why option C was chosen.

Read more about Effusion here brainly.com/question/2097955

#SPJ1

The options are:

diffusion because particles move from regions of high concentration to regions of low concentration.
diffusion because particles move from regions of low concentration to regions of high concentration.
effusion because there is a movement of a gas through a small opening into a larger volume.
effusion because there is a movement of a gas through a large opening into a smaller volume

You might be interested in

Use the collision theory to discuss how temp., concentration and surface area affect the rate of a chemical reaction?

pogonyaev

The collision theory explains how chemical reactions are made and different reactions have different reaction rates

Hope it helps.

4 0

3 years ago

CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7

padilas [110]

<u>Answer:</u> The $\Delta G$ for the reaction is 54.425 kJ/mol

<u>Explanation:</u>

For the given balanced chemical equation:

$CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)$

We are given:

$\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol$

To calculate $\Delta G^o_{rxn}$ for the reaction, we use the equation:

$\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]$

For the given equation:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J$

Conversion factor used = 1 kJ = 1000 J

The expression of $K_p$ for the given reaction:

$K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}$

We are given:

$p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm$

Putting values in above equation, we get:

$K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85$

To calculate the gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_p$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = $8.314J/K mol$

T = Temperature = $25^oC=[25+273]K=298K$

$K_p$ = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

$\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol$

Hence, the $\Delta G$ for the reaction is 54.425 kJ/mol

7 0

3 years ago

A single atom is in a balanced electrical state.

slega [8]

I believe the answer is: Protons and Neutrons
Protons weigh 1 amu while neutrons also weigh 1 amu. I’m not sure if they are talking about how many there is.

7 0

3 years ago

Read 2 more answers

Why don’t all of the particles in an atom contribute to the mass?

kotegsom [21]

Answer:

Explanation:

The mass of an atom is dependent on its number of protons and neutrons. Electrons have mass, but are too light in comparison to protons and neutrons to contribute towards the overall mass. Their relative mass is about 1/1840 compared to 1 for protons and neutrons, and therefore are not counted in the mass.

Hope this helped!

4 0

3 years ago

What can be said about an endothermic reaction with a negative entropy change?

zvonat [6]

The statement is false because endothermic reactions have a positive enthalpy change, because heat is being added to the system because it requires more energy to react

6 0

3 years ago