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lubasha [3.4K]
3 years ago
7

What type of rock is formed from particles laid down by water of wind? Igneous Sedimentary Metamorphic Crystal

Chemistry
2 answers:
Digiron [165]3 years ago
8 0
The best answer would be sedimentary rock because it forms from seiment and layers.
____ [38]3 years ago
5 0
Sedimentary rock. igneous is from lava  and metamorphic is caused by heat and pressure



brainliest answer?
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WILL MARK AS BRAINIEST PLEASE HELP 20 POINTS
Alisiya [41]

The subscript is the amount of atoms in each molecule and the coefficient is the amount of molecules. there are 4 Hydrogen, 2 Sulfur, and 8 Oxygen in this particular substance.

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3 years ago
How many grams are in0.465 moles of HCI​
MArishka [77]

Answer:

Explanation:

Amount HCl = 0.455mole

Molar mass = 1 + 35.5 = 36.5g/mol

Amount = mass/molar mass

:- mass = Amount × Molar mass

Mass = 16.97g

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Which condition In a nebula would prevent nuclear fusion
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A decrease in the overall volume of gases namely hydrogen would prevent nuclear fusion in a nebula.
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2 years ago
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A solution is created by dissolving 11.0 grams of ammonium chloride in enough water to make 235 mL of solution. How many moles o
Amanda [17]

Answer:

The correct answer is 0.206 moles

Explanation:

According to the given scenario, the calculation of the number of moles of ammonium chloride is available in the resulting solution is given below:

Given that

Amount of NH_4Cl is 11.0 grams

And, the volume is 235 mL

Now the molar mass of NH_4Cl is 53.49g/mol

So, the number of moles presented is

= 11.0 ÷ 53.49

= 0.206 moles

hence, the number of moles of ammonium chloride are available in the resulting solution is 0.206 moles

7 0
2 years ago
COCl2(g) decomposes according to the equation above. When pure COCl2(g) is injected into a rigid, previously evacuated flask at
mestny [16]

<u>Answer:</u> The value of K_p for the reaction at 690 K is 0.05

<u>Explanation:</u>

We are given:

Initial pressure of COCl_2 = 1.0 atm

Total pressure at equilibrium = 1.2 atm

The chemical equation for the decomposition of phosgene follows:

                  COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

Initial:            1                    -         -

At eqllm:       1-x                 x        x

We are given:

Total pressure at equilibrium = [(1 - x) + x+ x]

So, the equation becomes:

[(1 - x) + x+ x]=1.2\\\\x=0.2atm

The expression for K_p for above equation follows:

K_p=\frac{p_{CO}\times p_{Cl_2}}{p_{COCl_2}}

p_{CO}=0.2atm\\p_{Cl_2}=0.2atm\\p_{COCl_2}=(1-0.2)=0.8atm

Putting values in above equation, we get:

K_p=\frac{0.2\times 0.2}{0.8}\\\\K_p=0.05

Hence, the value of K_p for the reaction at 690 K is 0.05

3 0
2 years ago
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