I believe this question has the following five choices to
choose from:
>an SN2 reaction has occurred with inversion of
configuration
>racemization followed by an S N 2 attack
>an SN1 reaction has taken over resulting in inversion
of configuration
>an SN1 reaction has occurred due to carbocation
formation
>an SN1 reaction followed by an S N 2 “backside”
attack
The correct answer is:
an SN1 reaction has occurred due to carbocation formation
The concentration of NaOH is 25.00% by mass, it means that 25.00% of the mass of the solution is of NaOH. Hence:
Answer:
- 278.85 J
Explanation:
Given that:
Pressure = 1.1 atm
The initial volume V₁ = 0.0 L
The final volume V₂ = 2.5 L
The work that takes place in a reaction at constant pressure can be expressed by using the equation:
W = P(V₂ - V₁ )
Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:
W = - P(V₂ - V₁ )
W = -1.1 atm ( 2.5 - 0.0) L
W = -1.1 atm (2.5 L)
W = -2.75 atm L
Recall that:
1 atm L = 101.4 J
Therefore;
-2.75 atm L = ( -2.75 × 101.4 )J
= -278.85 J
Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm = - 278.85 J
Answer:
Rareness, the others describe what the gold is and its properties.
