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4 years ago

What is the relationship between the size of a predator population and the size of a prey population

1 answer:

3 0

Let's put it this way. Say you have a killer-whale and a penguin. Killer-whales are major predators to penguins. Now, say the killer-whale population increases. The penguins would be eaten more by the killer-whales, then causing a population decrease for the penguins. If the population decreases, they're won't be enough penguins, and they most likely will become extinct, as well as causing a population decrease for the killer-whales as well. Whereas, vis versa, they're were a killer-whale population decrease. The penguins would be less hunted, therefore, creating a population increase for the penguins.

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Huifen weighs herself on her bathroom scales.She says "My weight is 54 kg!"In Science, what Huifen said would be considered wron

navik [9.2K]

Answer:

That is her mass, not her weight

Explanation:

Weight is mass times gravity, which on Earth is 9.8m/s^2

7 0

3 years ago

A wave with a period of 1⁄3 second has a frequency of A. 67 Hz. B. 33 Hz. C. 300 Hz. D. 3 Hz.

Triss [41]

A wave with a period of 1⁄3 second has a frequency of D. 3 Hz. To calculate this we will use the formula that represents the correlation between a frequency (f) and a time period (T): T = 1/f. Or: f = 1/T. The unit for the time period is second "s" while the unit for frequency is Hertz "Hz" (=1/s). We know that T = 1/3 s. That means that f = 1/(1/3s) = 3 1/s = 3 Hz.

3 0

4 years ago

Which simple machine turns about a fixed point called a fulcrum? a pulley a lever a screw a wedge

leva [86]

Answer:

Lever

Explanation:

Fulcrum point is the point where the lever turns.

It is the center of a key activity

3 0

3 years ago

Read 2 more answers

A speaker at an open-air concert emits 600 W of sound power, radiated equally in all directions.

Marina86 [1]

Answer

Given,

Sound Power, P = 600 W

a) Intensity of sound,

r = 5 m

we know,

$I = \dfrac{P}{A}$

$I = \dfrac{P}{4\pi r^2}$

$I = \dfrac{600}{4\pi\times 5^2}$

I = 1.91 W/m²

b) Sound intensity

$\beta = 10 log(\dfrac{I}{I_0})$

I₀ = 10⁻¹²

$\beta = 10 log(\dfrac{1.91}{10^{-12}})$

$\beta = 123\ dB$

c) Sound experienced by the Phil

β₁ = 123 - 23 = 100 \ dB

distance from the sound

again using sound intensity formula

$\beta = 10 log(\dfrac{I}{I_0})$

$100= 10 log(\dfrac{I}{10^{-12}})$

$I = 10^{-12}\times 10^{10}$

where, I = P/A

$\dfrac{P}{4\pi r^2} = 10^{-2}$

$r^2 = \dfrac{600}{0.04\times \pi}$

r = 69.09 m

Distance where Phil will experience same sound intensity without earplug is equal to r = 69.09 m

7 0

4 years ago

In our new car, we were able to drive 30 miles in a half an hour. From this information, we can determine the car's

Nonamiya [84]

I am pretty sure that according to the information represened above, we can determine the car's speed. It is usual thing in physics tasks and when we are provided with such values, we can immediately reveal the characteristic of the speed. Hope it helps!

6 0

3 years ago

Read 2 more answers