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In-s [12.5K]
3 years ago
6

People working in nuclear plants wear special monitoring devices to track their exposure to radiation. Radioactive materials use

d in plants emit particles but they also emit high energy waves that are potentially lethal to human life. These waves are ______ waves
Physics
2 answers:
nevsk [136]3 years ago
5 0

Answer:

Gamma rays

Explanation:

Gamma rays are usually defined as a type of electromagnetic radiations, that are characterized by the presence of shorter wavelength and higher energy. These are the common radiations that are released from the radioactive substances, where an unstable nucleus of an atom releases an excess amount of energy by undergoing continuous electromagnetic processes.

These are harmful to humans and other organisms, as they are comprised of very high energy and they can easily penetrate through the bodies of humans and other organisms.

These gamma particles are emitted in the power plants, where the people working in it wear a special type of device that helps them in monitoring the exposure to radiation.

marissa [1.9K]3 years ago
3 0

It could also be gamma rays i don't really know

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1. Calculate the total heat content of 10 kg of ice at -23°C.?
vesna_86 [32]

To solve the problem, we must know the heat capacity of ice and water.

For Cp = 2090 J/kg C

H = mCpT

H = (10 kg) ( 2090 J/ Kg C) ( -23 C)

H = - 480700 J

For water Cp = 4180 j/kg C

H = (100 kg) ( 4180 J/kg C) ( 60 C)

<span>H = 2508000 J</span>

8 0
3 years ago
If two point sources of light are being imaged by this telescope, what is the maximum wavelength λ at which the two can be resol
Mrrafil [7]

Answer:

The maximum wavelength is 492 nm.

Explanation:

Given that,

Angular separation \theta=3.0\times10^{-5}\ rad

Suppose a telescope with a small circular aperture of diameter 2.0 cm.

We need to calculate the maximum wavelength

Using formula of angular separation

\sin\theta=\dfrac{1.22\lambda}{d}

\lambda=\dfrac{d\sin\theta}{1.22}

Put the value into the formula

\lambda=\dfrac{2.0\times\sin(3\times10^{-5})}{1.22}

For small angle \sin\theta\approx\theta

\lambda=\dfrac{0.02\times3\times10^{-5}}{1.22}

\lambda=4.92\times10^{-7}\ m

\lambda=492\ nm

Hence, The maximum wavelength is 492 nm.

5 0
3 years ago
A 3.0-kg object moves to the right with a speed of 2.0 m/s. It collides in a perfectly elastic collision with a 6.0-kg object mo
Zinaida [17]

Answer:

The kinetic energy of the system after the collision is 9 J.

Explanation:

It is given that,

Mass of object 1, m₁ = 3 kg

Speed of object 1, v₁ = 2 m/s

Mass of object 2, m₂ = 6 kg

Speed of object 2, v₂ = -1 m/s (it is moving in left)

Since, the collision is elastic. The kinetic energy of the system before the collision is equal to the kinetic energy of the system after the collision. Let it is E. So,

E=\dfrac{1}{2}m_1v_1^2+\dfrac{1}{2}m_2v_1^2

E=\dfrac{1}{2}\times 3\ kg\times (2\ m/s)^2+\dfrac{1}{2}\times 6\ kg\times (-1\ m/s)^2

E = 9 J

So, the kinetic energy of the system after the collision is 9 J. Hence, this is the required solution.

3 0
3 years ago
Interference is evidence of the particle nature of light.<br><br> True<br> False
Virty [35]
It's true answer that interference is the evidence of the particle nature of light..

3 0
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Answer:

C

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