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Anni [7]
3 years ago
12

For a circuit shown in the figure, all quantities are accurate in 3 significant figures. What is the power dissipated in 2-ohm r

esistor?
Physics
1 answer:
sergey [27]3 years ago
7 0
Base on your diagram it is a Series-Parallel type of connections right? So based on my calculation and the rule in computing the resistance and voltage of a parallel and series. The total resistance is 1.25 and the total voltage is 2.04 V
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A supply plane needs to drop a package of food to scientists working on a glacier in Greenland. The plane flies 90.0 m above the
romanna [79]

Answer:

d = 771.3m

Explanation:

Let's first calculate the time of flight:

Yf = Yo+Voy*t-g*t^2/2  where Voy=0. Solving for t:

t = \sqrt{2*90/9.8} =4.285s

Now we calculate the horizontal displacement, wihch is the distance from the target to drop the package:

Xf = d = Vox*t

d = 180*4.285 = 771.3m

6 0
3 years ago
An object has an initial velocity of 15 m/s. How long must it accelerate at a constant rate of 3. 0 m/s² before its final veloci
Lera25 [3.4K]

Answer: 5 sec

Explanation:

30 = 15 + (3*t)

so, t=(30-15)÷3

       = 5 sec

4 0
2 years ago
Help solve these two problems im having trouble trying to start these problems?​
belka [17]

Answer:

25.  Approximately 8.1 meters

26. North 1.31 km, and East 2.81 km

Explanation:

25.

Notice that the displacements: 6 meters east and 5.4 south create the legs of a right angle triangle. The hypotenuse of that triangle will be the distance (d) needed to cover in order to get the ball in the hole in one putt. That is:

d=\sqrt{6^2+5.4^2} =\sqrt{65.16} \approx 8.072\,\,\,m

which can be rounded to 8.1 m.

26.

Notice that the 3.1 km at an angle of 25 degrees north of east, is the hypotenuse of a right angle triangle that has for legs the east and north components of that distance.

We can find the leg corresponding to the east displacement using the cosine function (that relates adjacent side with hypotenuse):

east\,\, comp=3.1 * cos(25^o)\approx 2.809\,\,km

and we can calculate the north component using the sine function that relates the opposite side to the angle with the hypotenuse.

north\,\,component = 3.1 * sin(25^o) \approx 1.31 \,\,km

6 0
3 years ago
A 0.5 m3 container is filled with a fluid whose specific volume is 0.001 m3/kg. At standard gravitational acceleration, the cont
xenn [34]

Answer: the contents of this container weighs 4905 kg.m/s²

Explanation:

Given that;

volume of a container V = 0.5 m³

we know that standard gravitational acceleration g = 9.81 m/s²

specific volume of liquid filled in the container v = 0.001 m³/kg

now we express the equation for weight of the container.

W = mg

W = (pV)g

W = Vg / ν

so we substitute

W =  (0.5 m³)(9.81 m/s ) / 0.001 m³/kg

W = 4.905 / 0.001

W = 4905 kg.m/s²

Therefore, the contents of this container weighs 4905 kg.m/s²

5 0
3 years ago
What happens to a circuit's resistance (R), voltage (V), and current (1) when
hammer [34]

Answer:

D.

R increases

V is constant

I decreases

Explanation:

The resistance of a wire is given by the following formula:

R = \frac{(Resistivity)(L)}{A}

It is clear from this formula that resistance is directly proportional to the length of wire. So, when length of wire is increased, <u>the resistance of circuit increases</u>.

The <u>voltage in the circuit will be constant</u> as the voltage source remains same and it is not changed.

Now, we can use Ohm Law:

V = IR

at constant V:

I ∝ 1/R

it means that current is inversely proportional to resistance. Hence, the increase of resistance causes <u>the current in circuit to decrease.</u>

Therefore, the correct option will be:

<u>D.</u>

<u>R increases </u>

<u>V is constant </u>

<u>I decreases</u>

6 0
3 years ago
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