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Luda [366]
2 years ago
9

A horizontal force of 0.9N act on a body of mass 0.1kg there is resistance of 0.15 Newton opposing the first Force what accelera

tion will be produced​ please help​
Physics
1 answer:
natali 33 [55]2 years ago
7 0

Answer:

a = 7.5 [m/s²]

Explanation:

To solve this type of problem we must remember Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F = sum of forces [N]

m = mass = 0.1 [kg]

a = acceleration [m/s²]

Now replacing:

0.9-0.15=0.1*a\\a=7.5 [m/s^{2} ]

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An object is NOT accelerating if it is moving
Helga [31]

Answer:

At a constant speed

Explanation:

If a car is going 30 mph and it isnt going faster or slower, it is not accelerating but it is still moving

8 0
3 years ago
A plane travels down a runway 2750 m before it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1
ss7ja [257]

Answer: 4.236km

Explanation:

Let's define the point (x, y) as:

x = horizontal distance moved.

y = vertical distance moved.

If the plane starts in the point (0, 0) then:

"A plane travels down a runway 2750 m before it lifts off..."

At this time, the position will be:

P = (0 + 2750m, 0) = (2750m, 0).

"it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1.8 km since its wheels left the ground."

In this case, as the angle is measured from the horizontal, the components will be:

x = 1.8km*cos(37°) = 1.438km

y = 1.8km*sin(37°) =  1.083 km

Then the new position is:

P = (2750m + 1.438 km, 0 + 1.083 km)

Let's write it using the same units for all the quantities:

we know that

1km = 1000m

Then:

2750m = (2750/1000) km = 2.750 km.

Then we can write the new position as:

P = (2.750 km + 1.438km, 1.083km) = (4.188km, 1.083km)

Now, we define the displacement as the distance between the final position and the initial position.

The distance between two points (a, b) and (c, d) is:

D = √( (a  c)^2 + (b - d)^2)

In this case the points are:

(0, 0) for the initial position

(4.188km, 1.083km) for the final position.

And the displacement will be:

D = √( (4.188km - 0)^2 + (1.083 - 0)^2) = 4.236km

5 0
2 years ago
A car was moving at 14 m/s After 30 s, its speed increased to 20 m/s. What was the acceleration during this time ( need help fas
Arada [10]

Answer:let initial velocity u=14m/s

Final velocity v=20m/s

Time taken t=30

Acceleration =a

V=u +at

a= (20-14)/30

a=0.2m/s^2

Explanation:

Acceleration is the change in velocity with respect to time.

7 0
3 years ago
A car runs for about 10 years during its average useful life. If the odometer reads 120,000 miles at the end, what was the avera
Eva8 [605]

Answer:

12000 mph

Explanation:

Given that,

Distance read by the odometer = 120,000 miles

Duration of car, t = 10 years

We need to find the average speed of the car. Speed of an object is equal to the total distance covered divided by total time taken. So,

v=\dfrac{120000}{10}\\\\=12000\ mph

So, the average speed of the car is 12000 mph.

7 0
3 years ago
How many atoms of Carbon (C) are in 3CO2
viva [34]

Answer:

in co2 there is one atom of carbon

Explanation:

8 0
3 years ago
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