Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
* Mole ratio:
C2H4 + 3 O2= 2 CO2 + 2 H2O
1 mole C2H4 --------------- 2 moles H2O
8.00 moles C2H4 ---------- ?
8.00 x 2 / 1 => 16 moles of H2O
Therefore:
1 mole --------- 22.4 L at ( STP)
16 moles ------- ?
16 x 22.4 / 1 => 358.4 L
hope this helps!
Answer:
A.) Polymers are substances that have relatively large molecules
Answer:
The molar solubility of lead bromide at 298K is 0.010 mol/L.
Explanation:
In order to solve this problem, we need to use the Nernst Equaiton:
E is the cell potential at a certain instant, E⁰ is the cell potential, n is the number of electrons involved in the redox reaction, [ox] is the concentration of the oxidated specie and [red] is the concentration of the reduced specie.
At equilibrium, E = 0, therefore:
[red] = 0.010 M
The reduction will happen in the anode, therefore, the concentration of the reduced specie is equivalent to the molar solubility of lead bromide.
Explanation:
Given that,
Mass of metal cube, m = 20 g
Volume of cube, V =5 mL
We need to find the density of the cube. Mass per unit volume equals density.
So, the density of the cube is 4 g/ml.
We know that the density of Aluminium is 4 g/mL.
So, the cube is not Aluminium cube.