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Wittaler [7]
2 years ago
8

A mass of 100 kg is pulled by a 392 N force in the +X direction along a rough surface (uk=0.4) with uniform velocity v=20 m/s. W

hat is the TOTAL work done by ALL forces on the object after s=10 m?
Physics
1 answer:
alexdok [17]2 years ago
5 0

Answer:

The total work done will be zero.

Explanation:

Given that,

Mass = 100 kg

Force = 392 N

Velocity = 20 m/s

Distance s= 10 m

We need to calculate the work done

Using balance equation

The net force will be

F'=F-\mu mg

F'=392-0.4\times100\times9.8

F'=0

The net force is zero.

Hence, The total work done will be zero by all forces on the object.

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Klio2033 [76]

Answer:

Option c

Explanation:

Magnetic field lines form loops starting from north pole to south pole outside the magnet and from south pole to north pole inside the magnet.

Thus the field is such that it is directed outwards from the North pole and directed inwards to the South pole of the magnet.

A compass in a magnetic field will will comply with the magnet's North pole directing towards the magnetic field.

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At an oceanside nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water th
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Sound travels through a ​
attashe74 [19]

Answer:

A.3.64 m

Explanation:

Because

  • v=(fλ)
  • (1382)=(380)λ
  • λ=3.637m~3.64m

<em>where</em><em> </em><em>,</em><em>v</em><em>=</em><em>velocity</em>

<em>f</em><em>=</em><em>frequency</em><em> </em>

<em>λ</em><em>=</em><em>wave</em><em> </em><em>length</em><em> </em>

8 0
1 year ago
Read 2 more answers
A wall with a surface area of 10 m2 is 2.5 cm thick. The inner surface temperature of the wall is 4150C, but the outer surface i
klio [65]

Answer:

650.65 K or 377.5°C

Explanation:

Area = A = 10 m²

Thickness of wall = L = 2.5 cm = 2.5×10⁻² m

Inner surface temperature of wall = T_i = 415°C = 688.15 K

Outer surface temperature of wall = T_o

Heat loss through the wall = 3 kW = 3×10³ W

Thermal conductivity of wall = k = 0.2 W/m K

Assumptions made here as follows

  1. There is not heat generation in the wall itself
  2. The heat conduction is one dimensional
  3. Heat flow follows steady state
  4. The material has same properties in all directions i.e., it is homogeneous.

Considering the above assumptions we use the following formula

Q=\frac {T_i-T_o}{\frac{L}{kA}}\\\Rightarrow T_o=T_i-\frac {QL}{kA}\\\Rightarrow T_o=688.15-\frac {3\times 10^{3}\times 2.5\times 10^{-2}}{0.2\times 10}\\\Rightarrow T_o=650.65~K

∴ The temperature of the outer surface of the wall is 650.65 K or 377.5°C

5 0
3 years ago
A piano string having a mass per unit length equal to 4.80 x10^-3 kg/m is under a tension of 1200 N. Find the speed with which a
Travka [436]

Answer:

500m/s

Explanation:

From the question we are given the following;

mass per unit length = 4.80 x10^-3 kg/m

Tension T = 1200N

Speed of the wave is expressed as;

v = √T/m

v = √1200/0.0048

v = √250,000

v = 500m/s

Hence the speed at which the wave travels on this string is 500m/s

3 0
3 years ago
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