Question

A Plane has a takeoff speed of 150 m/s and requires 1500m to reach that speed. Determine the acceleration of the plane and the time required to reach this speed.

Answer 1

Answer:

The acceleration of the plane and the time required to reach this speed is  (a)= 7.5 $m/sec^2$ and time(t) = 20 seconds  

Explanation:

Given data Initial velocity $(V_i)$ = 0  

Final velocity ($V_f$) = 150 m/second

Distance (d) = 1500 m

We have the formula,  $\mathrm{V}_{\mathrm{f}}^{2}=\mathrm{V}_{\mathrm{i}}^{2}+2 \mathrm{ad}$

which gives $150^2$ = 0+2a(1500)    

22500 = 3000 a  

acceleration (a) = 7.5 $m/s^2$

$\mathrm{V}_{\mathrm{f}}=\mathrm{V}_{\mathrm{i}}+\mathrm{at}$

150 = 7.5 t

t= 150/7.5 = 20

t = 20 seconds.