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3 years ago

A pendulum takes 10 seconds to swing through 2 complete cycles what is it’s period and frequency

2 answers:

7 0

its period should be the amount it takes to cycle from cycle to cycle so it would be 10 and your frequency would have to be calculated by taking 10 and dividing by 2 since that is how many cycles you have done so your frequency is 5

plz mark me brainliest

eduard3 years ago

5 0

Period = (10 seconds) / (2 swings)

<em>Period = 5 seconds</em>

Frequency = (2 swings) / (10 seconds)

<em>Frequency = 0.2 per second.</em> (0.2 Hertz)

Notice that ...

Period = 1 / Frequency,

and

(period) x (frequency) = 1 .

These two things are true for every 'periodic' event ... anything that happens over and over and over and over and over. Like wave motion, your heart beat, or going to school.

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How to find volume metric

disa [49]

You multiply the high length and width and if your using centimeters then divide by 500 and then there's your answer.hoped this helped.

8 0

3 years ago

An archer draws her bow and stores 34.8 J of elastic potential energy in the bow. She releases the 63 g arrow, giving it an init

elena-14-01-66 [18.8K]

Answer:

Approximately $71\%$ .

Explanation:

The formula for the kinetic energy $\rm KE$ of an object is:

$\displaystyle \mathrm{KE} = \frac{1}{2}\, m \cdot v^2$ ,

where

$m$ is the mass of that object, and
$v$ is the speed of that object.

Important: Joule ( $\rm J$ ) is the standard unit for energy. The formula for $\rm KE$ requires two inputs: mass and speed. The standard unit of mass is $\rm kg$ while the standard unit for speed is $\rm m \cdot s^{-1}$ . If both inputs are in standard units, then the output (kinetic energy) will also be in the standard unit (that is: joules,

Convert the unit of the arrow's mass to standard unit:

$m = 63\; \rm g = 0.063\; \rm kg$ .

Initial $\rm KE$ of this arrow:

$\begin{aligned}\mathrm{KE} &= \frac{1}{2} \, m \cdot v^2 \\ &= \frac{1}{2}\times 0.063\; \rm kg \times \left(\rm 28 \; m \cdot s^{-1}\right)^2 \\ &\approx 24.696\; \rm J\end{aligned}$ .

That's the same as the energy output of this bow. Hence, the efficiency of energy transfer will be:

$\displaystyle \frac{24.696\; \rm J}{34.8\; \rm J} \times 100\% \approx 71\%$ .

8 0

3 years ago

The flow control circuit design that can best control an overrunning load is the ____ circuit.

lara31 [8.8K]

The meter out circuit is the flow control circuit design that can most effectively control an overrunning load.

The meter-out circuit can be very accurate, but are not efficient. The meter-out circuit can control overrunning as well as opposing loads while the other one method must be used with opposing loads only. The choice of flown control valve method and the location of the flow control in the circuit are dependent on the type of application being controlled.

<h3>What is a Circuit ?</h3>

In electronics, a circuit is a complete circular conduit through which electricity flows. A simple circuit consists of conductors, a load, and a current source. The term "circuit" broadly refers to any continuous path via which electricity, data, or a signal might flow.

The directional valve shifts, causing the actuator to move faster than pump flow can fill it due to an overrunning load. Oil is leaking from one side, whereas there is none on the other.

Hence, flow control circuit design that can best control an overrunning load is the opposing circuit

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3 0

2 years ago

two forces 3N and 4N act on a body in a direction due north and due East respectively calculate their equivalent

Lostsunrise [7]

Two forces 3N and 4N act on a body in a direction due north From East, the equilibrant's angle is given by $\theta=\tan ^{-1} \frac{3}{4}=36.8^{\circ}$ .

<h3>What are equilibrium and resultant force?</h3>

The equilibrium force is the balanced force when the net force acting is zero and is the exact opposite of the consequent force. The resultant force is one single force replaced by numerous forces.

<h3>Briefing:</h3>

3N and 4N are the two forces pulling on a body.

The forces work along the North and the East, which are perpendicular to one another.

The resultant of the forces, which is provided by the equilibrant force,

R = √(3)²+(4)²

R = 5N

From East, the equilibrant's angle is given by

$\theta=\tan ^{-1} \frac{3}{4}=36.8^{\circ}$

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6 0

1 year ago

The equation of a progressive

Juliette [100K]

Answer:

Amplitude = 0.02m

Frequency = 640 Hz

Wavelength, λ = 0.5m

v = 320 m/s

Explanation:

Given the wave equation :

y=0.02 sin2π/0.5 (320t - x) where x and y are in

meters and t is in second

Comparing the above relation with the general wave equation :

y(x, t) = Asin2π/λ(wt - kx)

The amplitude, A = 0.02

From the equation :

2π/0.5 = 2π/λ

λ = 0.5 m

320t = vt

Hence, v = 320 m/s

Recall :

v = fλ

320 = f * 0.5

f = 320 / 0.5

f = 640 Hz

6 0

3 years ago