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RUDIKE [14]
4 years ago
8

Draw and write shear strain equation

Engineering
1 answer:
Alchen [17]4 years ago
5 0

Answer:

\phi =\dfrac{\Delta L}{h}

Explanation:

Normal strain :

 It is the ratio of deformation to the original dimension.Normal strain occurs due to longitudinal force.

 Normal strain = ΔL/L

Shear strain:

It is the ratio of deformation to perpendicular dimension.Shear strain occurs due to tangential force.

From the second diagram:

tan\phi =\dfrac{\Delta L}{h}

if angle Φ is small then we can write

tan\phi =\phi

So

\phi =\dfrac{\Delta L}{h}

This is the shear strain equation.

 

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Technician A is correct. Technician B is wrong because a gear's transmission is used to increase or decrease torque.

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3 0
1 year ago
Which of the following is NOT a breach of Netiquette?
alexandr402 [8]

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Explanation:

7 0
3 years ago
1.8 A water flow of 4.5 slug/s at 60 F enters the condenser of steam turbine and leaves at 140 F. Determine the heat transfer ra
Ann [662]

Answer:

Hr=4.2*10^7\ btu/hr

Explanation:

From the question we are told that:

Water flow Rate R=4.5slug/s=144.78ib/sec

Initial Temperature T_1=60 \textdegree F

Final Temperature  T_2=140 \textdegree F

Let

Specific heat of water \gamma= 1

And

 \triangle T= 140-60

 \triangle T= 80\ Deg.F

Generally the equation for Heat transfer rate of water  H_r is mathematically given by

Heat transfer rate to water= mass flow rate* specific heat* change in temperature

 H_r=R* \gamma*\triangle T

 H_r=144.78*80*1

 H_r=11582.4\ btu/sec

Therefore

 H_r=11582.4\ btu/sec*3600

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3 0
3 years ago
A fluid of density 900 kg/m3 passes through a converging section of an upstream diameter of 50 mm and a downstream diameter of 2
NISA [10]

Answer:

Q= 4.6 × 10⁻³ m³/s

actual velocity will be equal to 8.39 m/s

Explanation:

density of fluid = 900 kg/m³

d₁ = 0.025 m

d₂ = 0.05 m

Δ P = -40 k N/m²

C v = 0.89

using energy equation

\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g} = \dfrac{P_2}{\gamma}+\dfrac{v_2^2}{2g}\\\dfrac{P_1-P_2}{\gamma}=\dfrac{v_2^2-v_1^2}{2g}\\\dfrac{-40\times 10^3\times 2}{900}=v_2^2-v_1^2

under ideal condition v₁² = 0

v₂² = 88.88

v₂ = 9.43 m/s

hence discharge at downstream will be

Q = Av

Q = \dfrac{\pi}{4}d_1^2 \times v

Q = \dfrac{\pi}{4}0.025^2 \times 9.43

Q= 4.6 × 10⁻³ m³/s

we know that

C_v =\dfrac{actual\ velocity}{theoretical\ velocity }\\0.89 =\dfrac{actual\ velocity}{9.43}\\actual\ velocity = 8.39m/s

hence , actual velocity will be equal to 8.39 m/s

6 0
3 years ago
If a car sits out in the sun every day for a long time can light from the sun damage the car paint
Reika [66]

Answer:

i think yes it could make the color go lighter

Explanation:

6 0
3 years ago
Read 2 more answers
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