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MrRa [10]
3 years ago
8

What Happens If A Sonic Boom Is Created?

Engineering
1 answer:
Volgvan3 years ago
8 0

Answer:

Explanation:

A sonic boom is a loud sound kind of like an explosion. It's caused by shock waves created by any object that travels through the air faster than the speed of sound. Sonic booms create huge amounts of sound energy. When an object moves through the air, it makes pressure waves in front of and behind it.

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I study to get good grades because my parents want to send me to the college of my choice.” This is an a. Intrinsic motivational
sashaice [31]

c. Both of These

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"A fluid at a pressure of 7 atm with a specific volume of 0.11 m3/kg is constrained in a cylinder behind a piston. It is allowed
AlekseyPX

Answer:

Work done by the fluid in the piston=164.5kJ/kg

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7 0
4 years ago
3–102 One of the common procedures in fitness programs is to determine the fat-to-muscle ratio of the body. This is based on the
gayaneshka [121]

Answer:

x_fat = [ 0.5*(Wsa + Wsw) -  p_muscle*V ] / V*( p_fat - p_muscle )

Explanation:

Given:

- The total volume of body = V

- The average density of the body = p_avg

- The density of muscle = p_muscle

- The density of fat = p_fat

Find:

Obtain a relation for the volume fraction of body fat x_fat

Solution:

- The volume of the fat is given by:

                          V_fat = x_fat*V

- The volume of the muscle is given by:

                          V_muscle = V - V_fat

                                            = V - x_fat*V

                                            =V*( 1 - x_fat )

- We will use the conservation of mass for the body related as:

                         mass_fat + mass_muscle = Total average mass

                         p_fat*V_fat + p_muscle*V_muscle = p_avg*V

                         p_fat*x_fat*V + p_muscle*V*( 1 - x_fat ) = p_avg*V

                         p_fat*x_fat + p_muscle*( 1 - x_fat ) = p_avg

- To determine p_1 we weigh the body in air:

                         Weight reading (Wsa) = m = p_1*V

                         p_1 = Wsa / V*g

- To determine p_2 we weigh the body in water:

                         Weight reading (Wsw) = m - p_w*V= p_1*V - p_w*V

                         Weight reading (Wsw) = V*(p_1 - p_w) = V*(p_2)

                         Where, p_2 = p_1 - p_water

                         p_2 = Wsw / V

- The average density p_avg:

                         p_avg = 0.5*(p_1 + p_2)  

                         p_avg = 0.5*(Wsa / V + Wsw / V)  

                         p_avg = 0.5*(Wsa + Wsw) / V                      

- Plug in the mass equation:

                         p_fat*x_fat + p_muscle*( 1 - x_fat ) = 0.5*(Wsa + Wsw) / V

                         x_fat*( p_fat - p_muscle ) = 0.5*(Wsa + Wsw) / V - p_muscle

                   x_fat = [ 0.5*(Wsa + Wsw) -  p_muscle*V ] / V*( p_fat - p_muscle )

                         

6 0
4 years ago
An existing building is suffering from cracks in the exterior walls. The investigating engineer wants to ensure that the foundat
jek_recluse [69]

Answer:

18 ft^{2}

Explanation:

Soil bearing pressure=\frac {Load}{Area}

Since we're given pressure of 2500 psf and load of 45000 pounds

The area=\frac {45000}{2500}=18

Therefore, the smallest area of safe footings should not be less than 18 ft^{2}

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A __________ defines the area of land that will supply water to a stream.
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drainage basin

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