Answer: You throw an object upwards from the ground with a velocity of 20m/s and it is subject to a downward
acceleration of 9.8 m/s2. How high does it go?
Given Formula Set up Solution
vi=20 m/s
vf=0 m/s
a=-9.8 m/s2
x=?
vf
2 = vi
2 + 2a x (0 m/s)2= (20 m/s)2 + 2 (-
9.8 m/s2) x
x=20.4 meters
Explanation: i known/ i hoped that helped.
Moment of force=fxd
Explain
M=fxd
The maximum height of the ball during this interval is 4.9 m (Option A)
<h3>How to determine the time to reach maximum height</h3>
The time taken to reach the maximum height can be obtained as follow:
- Time for the entire trip (T) = 2 s
- Time to reach maximum height (t) = ?
T = 2t
2 = 2t
Divide both side by 2
t = 2 / 2
t = 1 s
<h3>How to determine the maximum height reached by the ball</h3>
The maximum height reached by the ball can be obtained as follow:
- Acceleration due to gravity (g) = 9.8 m/s²
- Time to reach maximum height (t) =?
- Maximum height (h) =?
h = ½gt²
h = ½ × 9.8 × 1²
h = ½ × 9.8 × 1
h = 4.9 m
Thus, the maximum height reached by the ball is 4.9 m (Option A)
Learn more about motion under gravity:
brainly.com/question/22719691
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Answer:
10m/s
Explanation:
a = v- u/ t
=> v = at + u
= -2 × 5 + 20
= 10m/ s. ( 72 km/ h = 20 m/ s)
Answer:
<em>If you have any questions, comment</em>
Explanation:
a. time of flight =(2usinθ)/(g/6)
= 12usinθ/g
= (12x25xsin(30))/g
<h3>
= 15.306 seconds
</h3>
b. Range = u2sin(2θ)/(g/6)
= 6u2sin(2θ)/g
= (6x252xsin(60)) /9.8
= 331.387 metres
c. Range on earth = Range on moon/6 = 55.23 metres
On moon it travels 331.387 - 55.23 = 276.155 metres more than on earth