The freefall acceleration on the moon is 1/6 of its value on earth. suppose he hit the ball with a speed of 25m/s an angle of 30 above the horizontal.
1 answer:
Answer:
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Explanation:
a. time of flight =(2usinθ)/(g/6)
= 12usinθ/g
= (12x25xsin(30))/g
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= 15.306 seconds
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b. Range = u2sin(2θ)/(g/6)
= 6u2sin(2θ)/g
= (6x252xsin(60)) /9.8
= 331.387 metres
c. Range on earth = Range on moon/6 = 55.23 metres
On moon it travels 331.387 - 55.23 = 276.155 metres more than on earth
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