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MakcuM [25]
2 years ago
14

The freefall acceleration on the moon is 1/6 of its value on earth. suppose he hit the ball with a speed of 25m/s an angle of 30

above the horizontal.
a. how long was the ball in flight?
b. how far did it travel?
c. How much farther would it travel on the moon than on earth?
Physics
1 answer:
Umnica [9.8K]2 years ago
5 0

Answer:

<em>If you have any questions, comment</em>

Explanation:

a. time of flight =(2usinθ)/(g/6)

= 12usinθ/g

= (12x25xsin(30))/g

<h3>= 15.306 seconds </h3>

b. Range = u2sin(2θ)/(g/6)

= 6u2sin(2θ)/g

= (6x252xsin(60)) /9.8

= 331.387 metres

c. Range on earth = Range on moon/6 = 55.23 metres

On moon it travels 331.387 - 55.23 = 276.155 metres more than on earth

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To solve the problem above, we use the formula of impulse.

⇒ Formula:

  • I = m(v-u)................. Equation 1

Where:

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From the question,

⇒ Given:

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Hence, The Impulse delivered to the baseball is 89 kgm/s.

Learn more about impulse here: brainly.com/question/7973509

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