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MakcuM [25]
3 years ago
14

The freefall acceleration on the moon is 1/6 of its value on earth. suppose he hit the ball with a speed of 25m/s an angle of 30

above the horizontal.
a. how long was the ball in flight?
b. how far did it travel?
c. How much farther would it travel on the moon than on earth?
Physics
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer:

<em>If you have any questions, comment</em>

Explanation:

a. time of flight =(2usinθ)/(g/6)

= 12usinθ/g

= (12x25xsin(30))/g

<h3>= 15.306 seconds </h3>

b. Range = u2sin(2θ)/(g/6)

= 6u2sin(2θ)/g

= (6x252xsin(60)) /9.8

= 331.387 metres

c. Range on earth = Range on moon/6 = 55.23 metres

On moon it travels 331.387 - 55.23 = 276.155 metres more than on earth

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Many fundamental laws of physics and chemistry can be formulated when doing this.
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2 years ago
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You, Archimedes, suspect that the king’s crown is not solid gold but is instead gold-plated lead. To test your theory, you weigh
hjlf

Answer:

a) 16675.75 Kg/m³ b) 77.6%

Explanation:

the weight of the crown = 60 N, density of gold = 19300 Kg/m^3, density of lead = 11340 kg/m^3, density of water = 1000kg/m^3 and acceleration due to gravity = 9.8 m/s^2

upthrust on the crown = weight in air - weight when fully submerged in water = 60 - 56.4 = 3.6 N

mass of water displaced = 3.6 / 9.8  since weight = mass × g

mass of water displaced = 0.367 Kg

density of water = mass / volume

1000 = 0.367 / volume

cross multiply and find volume

volume of the crown = 0.367 / 1000 = 0.000367 m³ since the crown will displace water of equal volume according to Archimedes principle

Let V1 represent the volume of Gold and let V2 represent the volume of lead

Total volume of the crown = V1 + V2

also

density of gold = mass of gold / V1 and density of lead = mass of lead / V2

19300 = mass of gold in the crown / V1 and 11340 = mass of lead in the crown / V2

19300 V1 = mass of gold and 11340 V2 = mass of lead

add the two together

19300 V1 + 11340 V2 = weigth of the crown / 9.8

19300 V1 + 11340 V2 = 6.12 also

V1 + V2 = 0.000367

make V1 subject of the formula in equation 2

V1 = 0.000367 - V2

substitute for V1 in equation 1

19300 (0.000367 - V2) + 11340 V2 = 6.12

open the bracket

7.083 - 19300 V2 + 11340 V2 = 6.12

rearrange the equation

-7960 V2 = 6.12 - 7.083  

-7960 V2 = -0.963

V2 = -0.963 / -7960 = 0.000121 (volume of lead in the crown)

substitute V2 into equation 2

V1 + 0.000121  = 0.000367m³

V1 = 0.000367 - 0.000121 = 0.000246m³ (volume of gold in the crown)

so mass of gold in the crown = 19300 × 0.000246 = 4.748 kg

and mass of lead = 11340 × 0.000121 = 1.372 kg

average density of the crown = (mass of gold + mass of lead) / total volume = 6.12 / 0.000367 = 16675.75 kg/ m³

b) percentage make of gold = mass of gold / total mass × 100 = 77.6 % approx

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How many atoms of oxygen are there in one molecule of trinitrotoluene, if the chemical formula is C6H3(NO2)3?
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。☆✼★ ━━━━━━━━━━━━━━  ☾  

2 x 3 = 6

Thus there are 6 atoms of oxygen in this molecule.

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。☆✼★ ━━━━━━━━━━━━━━  ☾

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Yeah, hand signals are important in officiating games. The hand signals are given by the referee who first signals the fault and then indicates which team has won the point. A point is indicated by one finger at the side of the court to indicate the winner of the rally.

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If each side is 0.1 feet extra,
The volume will be 5.1*2.1*1.1= about 11.781.
Perhaps this helps.
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