<h2>
Answer:</h2>
Workdone = 601.33 Nm
<h2>
Explanation:</h2>
Workdone = Force(F) x horizontal distance(d).
Wordone = F x d
Where F is the horizontal component of the force
Force = 35 pounds
Recall that;
1 pound force = 4.4N
=> 35 pounds = 35 x 4.4N = 154N
=> Force = 154N
But since the rope makes a 10⁰ angle with the ground,
The horizontal component of the force F is Force x cos10⁰
=> F = 154 cos 10⁰
=> F = 154 x 0.9848
=> F = 151.66N
Horizontal distance (d) = 13 feet
Recall that;
1 foot = 0.305m
=> 13 feet = 13 x 0.305m = 3.965m
=> d = 3.965m
=> Substituting the values of F and d into the equation above, we have;
Workdone = F x d
Workdone = 151.66N x 3.965m
Workdone = 601.33Nm
Answer:
Force is needed to begin to move the book and force needed to keep the book moving at a constant velocity is 10.78 N and 5.85 N.
Explanation:
Given :
Mass of book , M = 2.03 kg.
Coefficient of static friction ,
Coefficient of kinetic friction ,
Force, required needed to begin to move the book ,
Now, We know kinetic friction acts when object is in motion .
Therefore , Force, required o keep the book moving at a constant velocity
Hence, this is the required solution.
The answer is:
A. Oxygen
Air contains more than one substance, water is chemically made up of oxygen and hydrogen, and sodium chlorine is a mixture of sodium and chlorine.
Hope it helps :)
Answer:
1.2 s
Explanation:
We'll begin by calculating the length (i.e distance) of the ramp. This can be obtained by using pythagoras theory as illustrated below:
NOTE: Length of the ramp is the Hypothenus i.e the longest side.
Let the Lenght of the ramp be 's'. The value of x can be obtained as follow:
s² = 4² + 3²
s² = 16 + 9
s² = 25
Take the square root of both side
s = √25
s = 5 m
Thus the length of the ramp is 5 m
Next, we shall determine the final velocity of the ball. This can be obtained as follow:
Initial velocity (u) = 3 m/s
Acceleration (a) = 2 m/s²
Distance (s) = 5 m
Final velocity (v) =?
v² = u² + 2as
v² = 3² + (2 × 2 × 5)
v² = 9 + 20
v² = 29
Take the square root of both side
v = √29
v = 5.39 m/s
Finally, we shall determine the time taken for the ball to reach the final position. This can be obtained as follow:
Initial velocity (u) = 3 m/s
Acceleration (a) = 2 m/s²
Final velocity (v) = 5.39 m/s
Time (t) =?
v = u + at
5.39 = 3 + 2t
Collect like terms
5.39 – 3 = 2t
2.39 = 2t
Divide both side by 2
t = 2.39 / 2
t = 1.2 s
Thus, it will take 1.2 s for the ball to get to the final position.