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kirza4 [7]
3 years ago
15

What did Aristotle believe?

Chemistry
1 answer:
Crank3 years ago
4 0

Answer:

C.) That all matter was composed of earth, fire, water and air

Explanation:

Just took the test

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Boiling point of the substance is directly proportional to
Mazyrski [523]

Answer:

The boiling point is directly proportional to the surface area which is proportional to the molecular weight.

Explanation:

6 0
3 years ago
1. How many molecules of water make up 1.00 MOLE?<br>I need how to solve it please.​
trapecia [35]

Answer:

6.022x10^23

Explanation:

Avogrado's number proved that one mole is equal to 6.022x10^23.

6 0
3 years ago
What else is found on earths atmosphere?
Cloud [144]
I mean the answer could just be rocks trees water stuff like that if that's what you eman
3 0
3 years ago
Are the bonds in each of the following substances ionic, nonpolar covalent, or polar covalent? (a)KCl (b)P4 (c)BF3 (d)SO2 (e)Br2
larisa [96]

Answer:

(a) Ionic

(b) Nonpolar covalent

(c) Polar covalent

(d) Polar covalent

(e) Nonpolar covalent

(f) Polar covalent

<em>For those substances with polar covalent bonds, which has the least polar bond?</em> NO₂

<em>For those substances with polar covalent bonds, which has the most polar bond?</em> BF₃

Explanation:

<em>Are the bonds in each of the following substances ionic, nonpolar covalent, or polar covalent?</em>

The nature of a bond depends on the modulus of the difference of electronegativity (|ΔEN|) between the atoms that form it.

  • If |ΔEN| = 0, the bond is nonpolar covalent.
  • If 0 < |ΔEN| ≤ 2, the bond is polar covalent.
  • If |ΔEN| > 2, the bond is ionic.

<em>(a) KCl</em>    |ΔEN| = |EN(K) - EN(Cl)| = |0.8 - 3.0| = 2.2. The bond is ionic.

<em>(b) P₄</em>      |ΔEN| = |EN(P) - EN(P)| = |2.1 - 2.1| = 0.0. The bond is nonpolar covalent.

<em>(c) BF₃</em>    |ΔEN| = |EN(B) - EN(F)| = |2.0 - 4.0| = 2.0. The bond is polar covalent.

<em>(d) SO₂</em>   |ΔEN| = |EN(S) - EN(O)| = |2.5 - 3.5| = 1.0. The bond is polar covalent.

<em>(e) Br₂</em>    |ΔEN| = |EN(Br) - EN(Br)| = |2.8 - 2.8| = 0.0. The bond is nonpolar covalent.

<em>(f) NO₂</em>   |ΔEN| = |EN(N) - EN(O)| = |3.0 - 3.5| = 0.5. The bond is polar covalent.

7 0
4 years ago
Azithromycin suspension dosing is 10 mg/kg/d and is available in 200mg/5ml doses. how many ml would a 25kg child receive daily?
bekas [8.4K]
The answer to this question is 6.25ml

To answer this question, you need to calculate the azithromycin drug doses for this patient. The calculation would be: 25kg * 10mg/kg/d= 250mg/d

Then multiply the doses with the available drug. It would be:
250 mg/d / (200mg/5ml)= 6.25ml/d
8 0
4 years ago
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