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shepuryov [24]
3 years ago
9

All of the following are true of bases except

Chemistry
2 answers:
AysviL [449]3 years ago
5 0
I am positive that it's A.
Oksana_A [137]3 years ago
4 0
All of these are correct except the first option, as Arrhenius bases increase the concentration of hydroxide ions.
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You put to chemicals in a bottle and screw on the lid.when you shake in the bottle starts to warm up what kind of reaction is th
Igoryamba
That experiment it's called a MRE bomb. That's why when you add the water to the chemicals in the bottle, it heats up causing the gasses to expand and then the bottle explodes. (It is a very dangerous experiment)

Hope I helped!

- Amber
3 0
3 years ago
Fill in the missing blanks in the equation below active enzyme
Anni [7]
There is no equation
4 0
3 years ago
The vapor pressure of substance X is 100. mm Hg at 1080.°C. The vapor pressure of substance X increases to 600. mm Hg at 1220.°C
artcher [175]

Explanation:

The given data is as follows.

         P_{1} = 100 mm Hg or \frac{100}{760}atm = 0.13157 atm

         T_{1} = 1080 ^{o}C = (1080 + 273) K = 1357 K

         T_{2} = 1220 ^{o}C = (1220 + 273) K = 1493 K

         P_{2} = 600 mm Hg or \frac{600}{760}atm = 0.7895 atm

          R = 8.314 J/K mol

According to Clasius-Clapeyron equation,

                   log(\frac{P_{2}}{P_{1}}) = \frac{\Delta H_{vap}}{2.303R}[\frac{1}{T_{1}} - \frac{1}{T_{2}}

            log(\frac{0.7895}{0.13157}) = \frac{\Delta H_{vap}}{2.303 \times 8.314 J/mol K}[\frac{1}{1357 K} - \frac{1}{1493 K}]

          log (6) = \frac{\Delta H_{vap}}{19.147}[\frac{(1493 - 1357) K}{1493 K \times 1357 K}]

                0.77815 = \frac{\Delta H_{vap}}{19.147J/K mol} \times 6.713 \times 10^{-5} K

              \Delta H_{vap} = 2.219 \times 10^{5} J/mol

                                   = 2.219 \times 10^{5}J/mol \times 10^{-3}\frac{kJ}{1 J}

                                    = 221.9 kJ/mol

Thus, we can conclude that molar heat of vaporization of substance X is 221.9 kJ/mol.

4 0
3 years ago
I don’t know if I’m right??
allochka39001 [22]

Answer:

what is this for? A-level..?!

Explanation:

3 0
3 years ago
Read 2 more answers
If you run the reaction to make water: 2H2 + O2 → 2H2O, starting with 3.0 moles of hydrogen gas and 2.0 moles of oxygen gas, wha
Alex_Xolod [135]

Answer:

54 g is the theoretical yield

Explanation:

This is the reaction:

2H₂ + O₂ → 2H₂O

So 2 moles of hydrogen react with 1 mol of oxygen, to produce 2 mol of water.

If I have 3 moles of H₂ and 2 moles of O₂, the my limiting reactant is the hydrogen.

1 mol of O₂ react with 2 moles of H₂

S 2 mol of O₂ would react with 4 moles (I only have 3 moles)

Then, ratio is 2:2 the same as 1:1

As 2 mol of H₂ produce 2 moles of water, 3 moles of H₂ will produce 3 moles of H₂O.

This is the theoretical yield in moles. Let's convert them to mass (mol . molar mass)

3 mol . 18g/m = 54 g

7 0
3 years ago
Read 2 more answers
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