It would be two, hope this helps
Let x be the time she ran and y be the time she walked
then distance ran = 25x and distance walked = 5y
so 15x + 5y = 42
and x + y = 4
* second equn. by -5:-
-5x - 5y = -20
add this to the first equn:0
10x = 22
x = 2.2
distance she ran = 2.2 * 15 = 33 km
Domain = set of input value
Range = set of output values
<h3>#1</h3>
- Domain: -2 < x ≤ 2 or (-2, 2]
- Range: -4 < y ≤ 4 or (-4, 4]
<h3>#2</h3>
- Domain: -5 ≤ x ≤ 1 or [-5, 1]
- Range: -1 ≤ y ≤ 5 or [-1, 5]
<h3>#3</h3>
- Domain: -4 < x < 4 or (-4, 4)
- Range: -1 ≤ y < 3 or [-1, 3)
If there is 5/8 of a total fuel supply on board, the ship can make 6 round trips
<u>Solution:</u>
Let the number of the round trips the ships make be "n"
Now, according to question in one trip the ship consumes
of its total fuel supply which is given to be 
Fuel supply used in "1" trip = 
Now fuel supply used for "n" trip is given as:


Hence the ship can make 6 round trips