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3 years ago

5

A 30 kg child is sitting on a swing. Their weight is exerting a downward force on the swing. The ropes are exerting an upward fo

rce on the swing. The swing is not moving. What is the net force on the swing?
A.294 N down
B.294 N up
C.0 N
D.30 kg

2 answers:

kvasek [131]3 years ago

7 0

Djgidodlckf dkdngrfndkckgdkckv

wariber [46]3 years ago

4 0

B.294 N up is the answers

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A) <u>Weight = mass × acceleration (due to gravity) </u>

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h = 1.7 m

<u>C) Kinetic energyF = potential energyI </u>

KEF = 1/2mv2

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3 years ago

A 7.0kg object rests on a horizontal frictionless surface. What is the magnitude of the horizontal

sukhopar [10]

Answer:

16.1 N

Explanation:

From the question,

F = ma.............................. Equation 1

Where F = horizontal force, m = mass of the object, a = acceleration .

Given: m = 7.0 kg, a = 2.3 m/s²

Substitute this values into equation 1

F = (7.0×2.3)

F = 16.1 N.

Hence the magnitude of the horizontal force is 16.1 N

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2 years ago

Buffalo, New York, and Raleigh, NC, lie approximately on the same meridian. Buffalo has a latitude of 42.9° N, and Raleigh has a

yulyashka [42]

Answer:

Distance will be $=3960\times 0.12385=490.468miles$

Explanation:

We have given that Buffalo has a latitude of 42.9°N

And Raleigh has a latitude of 35.8°N

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We have to calculate the distance between given two cities

Difference in their latitudes = $42.9-35.8=7.1^{\circ}$

Now changing the angle in radian = $7.1\times\frac{\pi }{180}=0.12385radian$

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2 years ago

Need help best answer will get brainiest

solong [7]

Answer:

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2 years ago

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Georgia [21]

Answer:

The space cadet that weighs 800 N on Earth will weigh 1,600 N on the exoplanet

Explanation:

The given parameters are;

The mass of the exoplanet = 1/2×The mass of the Earth, M = 1/2 × M

The radius of the exoplanet = 50% of the radius of the Earth = 1/2 × The Earth's radius, R = 50/100 × R = 1/2 × R

The weight of the cadet on Earth = 800 N

$The \ weight, W =G\dfrac{M \times m}{R^{2}} = 800 \ N$

Therefore, for the weight of the cadet on the exoplanet, W₁, we have;

$W_1 =G\dfrac{\dfrac{M}{2} \times m}{ \left ( \dfrac{R}{2} \right ) ^{2}} = G\dfrac{\dfrac{M}{2} \times m \times 4}{ R ^{2}} = 2 \times G \times \dfrac{M \times m}{R^{2}} = 2 \times 800 \, N = 1,600 \, N$

The weight of a space cadet on the exoplanet, that weighs 800 N on Earth = 1,600 N.

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2 years ago