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Marta_Voda [28]
3 years ago
10

Draw the structure of the compound formed from propanoic acid and dimethylamine

Chemistry
1 answer:
jeyben [28]3 years ago
7 0

 The compound form from propanoic acid and dimethylamine is 3-(dimethylamino)propanoic acid. Propanoic acid is a liquid carboxylic acid that has pungent and unpleasant smell resembling to body odor. Its chemical formula is C2H5C00H. Moreover, dimethylamine is an organic compound and a secondary amine that is colorless, flammable gas with an ammonia like odor. Its chemical formula is (CH3)2NH.

The 2D structure is attached here.

 

                                                                        

                          

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Answer:

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General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

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Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 412.072 \ g \ Cl_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

412.072 g Cl₂ ≈ 412 g Cl₂

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