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Marta_Voda [28]
3 years ago
10

Draw the structure of the compound formed from propanoic acid and dimethylamine

Chemistry
1 answer:
jeyben [28]3 years ago
7 0

 The compound form from propanoic acid and dimethylamine is 3-(dimethylamino)propanoic acid. Propanoic acid is a liquid carboxylic acid that has pungent and unpleasant smell resembling to body odor. Its chemical formula is C2H5C00H. Moreover, dimethylamine is an organic compound and a secondary amine that is colorless, flammable gas with an ammonia like odor. Its chemical formula is (CH3)2NH.

The 2D structure is attached here.

 

                                                                        

                          

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Describe the test for hydrogen. Give the result of the test.
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Answer:

A simple test for the prescence of hydrogen gas is to light a splint and put it in the smoke present. If it makes a squeaky pop sound, then hydrogen gas is present. The hydrogen gas produced is combustible, and will therefore burn when it reacts with oxygen gas

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3 years ago
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Use the graph to answer these questions. For numerical answers, use correct significant digits.
kykrilka [37]

Answer:

  • 1. Letter <u>    A      </u>shows the overall enthalpy of reaction

  • 2. which is equal to kJ  <u>   2,538.90kJ   </u>

  • 3. Letter <u>    B     </u>shows the activation energy for the reaction

  • 4. The activated complex is represented by <u>   letter C   </u>

Explanation:

<em></em>

<em>1. Letter __ shows the overall enthalpy of reaction</em>

The overall enthalpy of reaction is equal to the change of enthalpy of the substances:

Enthalpy of reaction = ∑ enthalpy of the products - ∑enthalply of the reactants.

The products are shown of the right side of the diagram. They are C₆H₁₂O₆(g) and 6O₂(g).

The reactants are shown of the left side of the diagram. They are 6CO₂(g) and 6H₂O(g).

The arrow labeled A shows the difference between the enthalpies of the products and the reactants; thus this shows the overall enthalpy of reaction.

<em></em>

<em>2. which is equal to kJ__</em>

You must subtract the enthalpy of the iniital state (reactants) from the enthalpy of the final state (products).

  • Overall enthalpy of reaction = - 1,273.02kJ - ( - 3,811.92kJ)
  • Overall enthalpy of reaction = 2,538.90kJ

This is a positive change indicating the reaction is endothermic.

<em>3. Letter___shows the activation energy for the reaction</em>

The activation energy is the energy that the reactants must gain for the reaction occurs.

Thus, it is the difference between the maximum energy, indicated by the label C on the graph, and initial state.

That is shown by the arrow labeled B: the reactants must gain the amount of energy indicated by the arrow labeled B to reach the energy of the state labeled C.

<em>4. The activated complex is represented by ____</em>

<em />

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The activated complex is on the top of the energy diagram because it hat the highest energy. The formation of the activated complex always requires energy (it is an endothermic process). Once it is formed, energy is released and the reactants are formed (this part is exothermic).

Thus, the activated complex is labeled with the letter C.

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