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3 years ago

Something with a density greater than 1.00 g ml

1 answer:

5 0

Something with a density greater than 1.00 g ml will sink in waterThe density of water is 1 gm/cm^3=1000 kg/m^3, therefore, any element or object with density greater than 1 will sink in water.
Examples of elements with density greater than 1:
Aluminum (2700 kg/m^3 = 2.7 gm/cm^3)
Nickel ( 8910 kg/m^3 = 8.91 gm/cm^3)

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What type(s) of intermolecular forces are expected between seh2 molecules?

bija089 [108]

London dispersion
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2 years ago

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A solution of KMnO4 has an absorbance of 0.539 when measured in the colorimeter. Determine the concentration of the KMnO4 given

loris [4]

Answer:

Concentration of unknown solution is 0.0416 M

Explanation:

As we know

Absorbance is equal to the product of molar absorptivity of KMnO4 m, path length and concentration

From the given set of graphical data, it is clear that the absorbance vs concentration is a straight line.

From the graph, we can obtain-

Y = 5.73 X – 0.0065

Absorbance = 0.232

0.232 = 5.73 X – 0.0065

X = 0.0416

Concentration of unknown solution is 0.0416 M

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2 years ago

15.1 L N2 at 25 °C and 125 kPa and 44.3 L O2 at 25 °C and 125 kPa were transferred to a tank with a volume of 6.25 L. What is th

Y_Kistochka [10]

Answer:

The total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.

Explanation:

For N2,

Pressure(P₁)=125 kPa

Volume(V₁)=15·1 L

Temperature (T₁)=25°C=25+273 K=298 K

Similarly, for Oxygen,

Pressure(P₂)= 125 kPa

Volume(V₂)= 44.3 L

Temperature(T₂)=25°C= 298 K

Then, for the mixture,

Volumeof the mixture( V)= 6.25 L

Pressure(P)=?

Temperature (T)= 51°C = 51+273 K=324 K

Then, By Combined gas laws,

$\frac{P_{1} V_{1} }{T_{1} } +\frac{P_{2} V_{2} }{T_{2} } =\frac{PV}{T}$

or, $\frac{15.1*125}{298} +\frac{44.3*125}{298} =\frac{P*6.25}{324}$

or, $6.34+18.58=\frac{P*6.25}{324}$

or, $P=\frac{24.92*324}{6.25}$

∴P=1291.85 kPa

So the total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.

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2 years ago

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The Answer To This Is B.

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