Answer : The concentration after 17.0 minutes will be, 
Explanation :
The expression for first order reaction is:
![[C_t]=[C_o]e^{-kt}](https://tex.z-dn.net/?f=%5BC_t%5D%3D%5BC_o%5De%5E%7B-kt%7D)
where,
![[C_t]](https://tex.z-dn.net/?f=%5BC_t%5D)
= concentration at time 't' (final) = ?
![[C_o]](https://tex.z-dn.net/?f=%5BC_o%5D)
= concentration at time '0' (initial) = 0.100 M
k = rate constant = 
t = time = 17.0 min = 1020 s (1 min = 60 s)
Now put all the given values in the above expression, we get:
![[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}](https://tex.z-dn.net/?f=%5BC_t%5D%3D%280.100%29%5Ctimes%20e%5E%7B-%285.40%5Ctimes%2010%5E%7B-3%7D%29%5Ctimes%20%281020%29%7D)
![[C_t]=4.05\times 10^{-4}M](https://tex.z-dn.net/?f=%5BC_t%5D%3D4.05%5Ctimes%2010%5E%7B-4%7DM)
Thus, the concentration after 17.0 minutes will be,
I would go with 7 because its just water.
Answer:
T2 = 36.38°C
Explanation:
Given data:
Mass of water = 75 g
Initial temperature = 30 °C
Final temperature = ?
Heat absorbed = 2000 J
Solution:
Specific heat capacity of water is 4.18 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - initial temperature
2000 J = 75 g×4.18 J/g.°C × T2- T1
2000 J = 313.5 J/°C × T2- T1
2000 J = 313.5 J/°C × T2 - 30 °C
2000 J / 313.5 J/°C = T2 - 30 °C
6.38 °C = T2 - 30 °C
T2 = 6.38 °C + 30°C
T2 = 36.38°C
Answer:
question two is most likely you can describe the shape as a twisted ladder, thats what I learned in school.
Explanation:
YW
