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3 years ago

Something with a density greater than 1.00 g ml

1 answer:

5 0

Something with a density greater than 1.00 g ml will sink in waterThe density of water is 1 gm/cm^3=1000 kg/m^3, therefore, any element or object with density greater than 1 will sink in water.
Examples of elements with density greater than 1:
Aluminum (2700 kg/m^3 = 2.7 gm/cm^3)
Nickel ( 8910 kg/m^3 = 8.91 gm/cm^3)

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I really need help with this!

Lady bird [3.3K]

Answer:

Explanation:

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3 years ago

What is the symbol for moles using the ideal gas equation

vredina [299]

Answer: N is the numbers of moles

Explanation:

An ideal gas can be characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them may be deduced from kinetic theory and is called the. n = number of moles. R = universal gas constant = 8.3145 J/mol K. N = number of molecules.

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3 years ago

If environmental scientists want to publish a paper on an experiment for an audience of fellow speacialist where do they do so

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It would be c. Newspaper story

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3 years ago

Read 2 more answers

A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157g of the compound produced 0.213g of CO2 and

vladimir2022 [97]

Answer:

$C_{7} H_{5}N_{3}O_{6}$

Explanation:

First reaction gives you the number of moles or the mass from Carbon and hydrogen

for carbon:

$0,213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} =0.005molC$

$0.213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} .\frac{12gC}{1molC} = 0.058gC\\$

Analogously for hydrogen:

0.0310g $H_{2}O$ have 0.0034gH or 0.0034mol of H

In the second reaction you can obtain the amount of nitrogen as a percentage and find the mass of N in the first sample.

$0.023gNH_{3} .\frac{1molNH_{3}}{17gNH_{3}} .\frac{1molN}{1molNH_{3}} .\frac{14gN}{1molN} \frac{100}{0.103gsample} =18.4%N$

now

$\frac{18.4gN}{100gsample} .0.157gsample=0.0289gN in the first reaction$

this is equivalet to 0.002mol of N

with this information you can find the mass of oxygen by matter conservation.

$gO=total mass-(gN+gC+gH)=0.157-(0.0289+0.058+0.0034)=0.0666gO$

this is equivalent to 0.004molO

finally you divide all moles obtained between the smaller number of mole (this is mol of H)

$C\frac{0.0048}{0.0034} H\frac{0.0034}{0.0034} N\frac{0.002}{0.0034} O\frac{0.004}{0.0034} =C_{1.4} HN_{0.6} O_{1.2}$

and you can multiply by 5 to obtain: $C_{7} H_{5}N_{3}O_{6}$

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3 years ago

Identify the acid and conjugate base pair in the following equation:

Serjik [45]

Answer:

hola no ablo inalgun moderador puede acabar a este otro este me borró respuesta que no debió borrar

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3 years ago