Answer:
A
Explanation:
idk but i do know its right
There is no reaction because of the common ion effect(which in this case is K)if there were a reaction the products would be the same as the reactants so no reaction happens
We first assume that this gas is an ideal gas where it follows the ideal gas equation. The said equation is expressed as: PV = nRT. From this equation, we can predict the changes in the pressure, volume and temperature. If the volume and the temperature of this gas is doubled, then the pressure still stays the same.
Answer:
Final volumeof the gas = 2.84 L
Explanation:
The formular to be used here is the general gas equation. the formular is being used because it gives the relationship between the three gas parameters (volume, temperature and pressure) mentioned.
The general gas equation is given as;
where;
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = Final pressure
V2 = Final volume
T2 = Final temperature
From the question,
P1 = 1.00 atm
P2 = 0.85atm
T1 = 25C + 273 = 298K (Converting to kelvin)
T2 = 15C + 273 = 288K (Converting to kelvin)
V1 = 2.5L
V2 = ?
from the equation, making V2 subject of formula we have;
V2 = (1*2.5*288)/(298*0.85) = 2.84 L.
Answer:
The correct option is: B. Carbon 5 only
Explanation:
Carvone is a naturally-occurring monoterpenoid consisting of a six-membered cyclic ring. <u>The </u><u><em>carbon-5</em></u><u> of this cyclic ring of Carvone is </u><u><em>chiral, </em></u><u>due to which Carvone exhibits </u><u><em>enantiomerism</em></u><u>.</u>
The two <em>enantiomeric forms</em> of Carvone are: R-(–)-carvone, or L-carvone, and S-(+)-carvone, or D-carvone.
<em><u>These two enantiomeric forms differ in the orientation of the substituents on the chiral carbon-5.</u></em>
<u />
<u>Therefore, the correct option is B. Carbon 5 only.</u>
