The equation for that is 25+(.05x25) or $26.25
Answer: The sailboat is at a distance of 15 km from the port.
Step-by-step explanation: Given that a sail boat leaves port and sails 12 kilometers west and then 9 kilometers north.
We are to find the distance between the sailboat from the port in kilometers.
Since the directions west and north are at right-angles, we can visualize the movement of the sailboat in the form of a right-angled triangle as shown in the attached figure.
The sailboat moves leaves the port at P and reach O after sailing 12 km west. From point O, again it moves towards north 9 km and reach the point S.
PS = ?
Using the Pythagoras theorem, we have from right-angled triangle SOP,
Thus, the sailboat is at a distance of 15 km from the port.
The answer is D. 60/100
In order to get the denominator from 5 to 100, you must multiple it by 20, meaning you also have to do that to the numerator. 3x20=60, therefore, the answer is 60/100
We can use the 9 inches wide to determine that 18 inches of the 42 inches are the wide sides. 42 - 18 = 24, so we divide 24 by how many long sides there are, 2. 24 ÷ 2 = 12. The box was 12 inches long.
9. 10x + 5y is the equation for larger watermelons + smaller watermelons (you did not provide information about the medium watermelons, so we must assume given the options you miswrote one of them). We can hold NO MORE than 500 pounds, so 10x + 5y must be smaller than 500. The best answer is C assuming that "5y" represents your "Medium Watermelons"- because smaller watermelons are stated to be 5 and medium ones should therefore be between 5 and 10, the option provided by A wouldn't make since because 3 pounded watermelons are not "medium" in comparison to the "small ones" that are heavier/bigger. Your best option is C, 10x + 5y < 500, the exact answer technically would be 10x + 5y <= 500.
