The grams of oxygen that are produced is 228.8 grams
<em>calculation</em>
2H₂O₂ → 2H₂O +O₂
Step 1: use the mole ratio to determine the moles of O₂
from equation above H₂O₂:O₂ is 2:1
therefore the moles of O₂ = 14.3 moles ×1/2 = 7.15 moles
Step 2: find mass of O₂
mass = moles × molar mass
= 7.15 moles × 32 g/mol =228.8 g
Ne is the smallest
B is the biggest
It goes (smallest to largest) : Ne, F,C,B
To solve this we assume that the hydrogen gas is an
ideal gas. Then, we can use the ideal gas equation which is expressed as PV =
nRT. At a constant pressure and number of moles of the gas the ratio T/V is
equal to some constant. At another set of condition of temperature, the
constant is still the same. Calculations are as follows:
T1 / V1 = T2 / V2
V2 = T2 x V1 / T1
V2 = (100 + 273.15) K x 2.50 L / (-196 + 273.15) K
<span>V2 = 12.09 L</span>
Therefore, the volume would increase to 12.09 L as the temperature is increased to 100 degrees Celsius.
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Answer:
270
Explanation:
Once you add more mass to something the mass doesn’t go away you add more mass.
hope this helps!
<span>the answer is c. energy</span>
