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Viefleur [7K]
3 years ago
6

What change in atomic number occurs when a nucleus emits an alpha particle? a beta particle? a gamma ray?

Chemistry
1 answer:
marissa [1.9K]3 years ago
7 0

1. Alpha decay

Alpha particle is a ₂⁴He nucleus. When a parent atom emits an alpha particle, the atomic number reduces by 2 in the formed daughter atom while reducing the mass number by 4. Since atomic number = proton number, due to the decreasing of atomic number, proton number also reduces by 2 in daughter nucleus.


2. Beta emission.

There are two types of beta decay. One is β⁻ and other one is β⁺ emission.

β⁻ emission

β⁻ emission is an emission of an electron by converting a neutron to a proton. Hence, in β⁻<span> decay, the atomic number increases by 1 and mass number is not changed in the formed daughter nucleus.</span>

β⁺ emission

β⁺ emission is an emission of an positron while converting a neutron to a proton. Hence, in β⁺ <span>decay, the atomic number decreases by 1 and mass number is not changed in the formed daughter nucleus.</span>

<span>
</span>

3. Gamma decay

In Gamma decay there is no any particle decay from the parent nucleus. Unstable nucleus emits energy photon and becomes as stable by undergoing a gamma decay. Hence, there is no change in atomic number or mass number of the daughter atom.

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butalik [34]

The H3O+  concentration  of the solution with  a PH  of 3.60  is  2.5  x10^-4 M (answer  A)


   <u><em>explanation</em></u>

PH is calculated  using PH = - log  [ H3O+]  formula


Therefore  - log [H3O+]  = 3.60

To calculate  the concentration of h3O+  ,find the  antilog  of 3.60

Since  -log is at base of 10, the antilog  of 3.60  = 10^-3.60  = 2.5 x10^-4M

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3 years ago
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Answer:

physical

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4 years ago
How many grams of tris (mw 121.1) would you need to prepare 100 ml of a 100 mm tris solution? _________ grams?
Tems11 [23]

Molarity = (Mass/ molar mass) x (1/ volume of solution in Litres)

Mass = Molarity x molar mass x  volume of solution in Litres

Molarity of Tris = 100 mM = 0.1 M

volume of Tris sol. = 100 mL = 0.1 L

molar mass of Tris = 121.1 g/mol

Hence,

mass of Tris = Molarity of Tris x molar mass ofTris x volume of Tris solution

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7 0
4 years ago
How much heat is absorbed by a 112.5 g sample of water when it is heated from 12.5 °C to 92.1 °C? (Specific heat capacity of wat
Alborosie

Answer:

\boxed {\boxed {\sf37,467.72 \ Joules }}

Explanation:

We are asked to find how much heat a sample of water absorbed. Since we are given the mass, temperature, and specific heat, we will use the following formula.

q=mc \Delta T

The mass (m) of the sample is 112.5 grams. The specific heat capacity of water (c) is 4.184 Joules per gram degree Celsius. The difference in temperature (ΔT) is found by subtracting the initial temperature from the final temperature.

  • ΔT= final temperature - initial temperature

The water was heated from 12.5 degrees Celsius to 92.1 degrees Celsius.

  • ΔT= 92.1 °C - 12.5 °C= 79.6°C

Now we know three variables and can substitute them into the formula,

  • m= 112.5 g
  • c= 4.184 J/g °C
  • ΔT= 79.6 °C

q= (112.5 \ g )(4.184 \ J/g \textdegree C)(79.6 \textdegree C)

Multiply the first 2 numbers. Note the units of grams cancel.

q= (112.5 \ g *4.184 \ J/g \textdegree C)(79.6 \textdegree C)

q= (112.5  *4.184 \ J/ \textdegree C)(79.6 \textdegree C)

q= (470.7 \ J/ \textdegree C)(79.6 \textdegree C)

Multiply again. This time the units of degrees Celsius cancel.

q= (470.7 \ J/ \textdegree C *79.6 \textdegree C)

q= (470.7 \ J *79.6 )

q= 37467.72 \ J

37, 467.72 Joules of heat are absorbed by the sample fo water.

7 0
3 years ago
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