The H3O+ concentration of the solution with a PH of 3.60 is 2.5 x10^-4 M (answer A)
<u><em>explanation</em></u>
PH is calculated using PH = - log [ H3O+] formula
Therefore - log [H3O+] = 3.60
To calculate the concentration of h3O+ ,find the antilog of 3.60
Since -log is at base of 10, the antilog of 3.60 = 10^-3.60 = 2.5 x10^-4M
Answer:
physical
Explanation:
it is physical because you add another chemical to the sodium
<span>Chemical and physical actions of groundwater form </span>Karst topography.
Molarity = (Mass/ molar mass) x (1/ volume of solution in Litres)
Mass = Molarity x molar mass x volume of solution in Litres
Molarity of Tris = 100 mM = 0.1 M
volume of Tris sol. = 100 mL = 0.1 L
molar mass of Tris = 121.1 g/mol
Hence,
mass of Tris = Molarity of Tris x molar mass ofTris x volume of Tris solution
= 0.1 M x 121.1 g/mol x 0.1 L
= 1.211 g
mass of Tris = 1.211 g
Answer:

Explanation:
We are asked to find how much heat a sample of water absorbed. Since we are given the mass, temperature, and specific heat, we will use the following formula.

The mass (m) of the sample is 112.5 grams. The specific heat capacity of water (c) is 4.184 Joules per gram degree Celsius. The difference in temperature (ΔT) is found by subtracting the initial temperature from the final temperature.
- ΔT= final temperature - initial temperature
The water was heated from 12.5 degrees Celsius to 92.1 degrees Celsius.
- ΔT= 92.1 °C - 12.5 °C= 79.6°C
Now we know three variables and can substitute them into the formula,
- m= 112.5 g
- c= 4.184 J/g °C
- ΔT= 79.6 °C

Multiply the first 2 numbers. Note the units of grams cancel.



Multiply again. This time the units of degrees Celsius cancel.



37, 467.72 Joules of heat are absorbed by the sample fo water.