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rjkz [21]
3 years ago
7

In which block of the periodic table is chromium (Cr) found? s block d block p block f block

Chemistry
2 answers:
Aneli [31]3 years ago
6 0

<u>Answer:</u> The correct answer is d-block.

<u>Explanation:</u>

Chromium is the 24th element of the periodic table. It belongs to period 4 and Group 6 of the periodic table.

The number of electrons present in this element are 24 because number of electrons is equal to the atomic number of the element.

Electronic configuration of this element is: [Ar]4s^23d^4

As, the last electron is entering the d-orbital. Hence, this element belongs to d-block of the periodic table.

amm18123 years ago
3 0
Chromium is currently found in block d according to the periodic table so you should get d block as your correct answer.
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The area in which certain types of plants or animals can be found living in close proximity to each other is called a_________
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I think the answer to this is A
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what would you be most likely to measure by immsering and object in water and seeing how much the water level rises
Katena32 [7]
Mass, if you know what element you are working with.
4 0
3 years ago
1. A 2-kg bowling ball sits on top of a building that is 40 meters tall. (5 pts) Circle one: KE / GPE / both ( can you show work
masha68 [24]
Potential energy is energy due to an object's height above the ground.
Potential energy = mass x gravity x height
Kinetic energy is energy due to the motion of the object.
Kinetic energy = 1/2 x mass x velocity²

1.
The ball is not moving and is at a height above the ground so it has only potential energy.
P.E = 2 x 9.81 x 40
P.E = 784.8 J

2.
The ball is moving and has a height above the Earth's surface so it has both kinetic and potential energy.
P.E = same as part 1 = 784.8 J
K.E = 1/2 x 2 x 5²
K.E = 25 J

3.
The ball has no height above the Earth's surface and is moving so it has only kinetic energy.
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K.E = 100 J

4.
50000 = 1/2 x 1000 x v²
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5.
39200 = 200 x 9.81 x h
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3 0
3 years ago
How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)
Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g

To calculate the heat absorbed by the water, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(100-25)^oC=75^oC

Putting values in above equation, we get:

q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

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3 years ago
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