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Sindrei [870]
3 years ago
6

Simplify: (8^2/3)^4​

Mathematics
2 answers:
kodGreya [7K]3 years ago
6 0
In fraction form, it’s 213333^4/ 10,000^4
Lapatulllka [165]3 years ago
6 0

Answer:

(8^{\frac{2}{3} } )^{4} = 256

Step-by-step explanation:

Given

(8^{\frac{2}{3} } )^{4}

Required

Simplify

To simplify this, we apply law of indices but first we start by solving the expression in bracket.

8 =2 * 2 * 2

8 = 2³

So, we substitute 2³ for 8

(8^{\frac{2}{3} } )^{4} becomes

((2^{3})^{\frac{2}{3} } )^{4}

From law of indices

a^{n} = (a^{m})^{\frac{n}{m} } ==> (a^{m})^{\frac{n}{m} } = a^{n}

So, (2^{3})^{\frac{2}{3} } = 2^{2}

At this point we have

((2^{3})^{\frac{2}{3} } )^{4} = (2^{2})^{4}

Also, from law of indices

(a^{m})^{n} = a^{m.n}

So,

((2^{3})^{\frac{2}{3} } )^{4} = (2^{2})^{4}

(2^{2})^{4} = 2^{2*4}

(2^{2})^{4} = 2^{8}

(2^{2})^{4} = 256

Hence,

(8^{\frac{2}{3} } )^{4} = 256

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Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter
MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

R_{3} = (x) = (e^z /4!)x^4

Since the aim is R_{3}(x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 0
3 years ago
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