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son4ous [18]
3 years ago
9

) Determining the order of events and the relative age of rocks by examining the position of

Physics
1 answer:
tigry1 [53]3 years ago
5 0
The answer is c; relative dating
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A car is accelerated from 40 m/s to 48 m/s in 6.5 seconds. What is the magnitude of the car’s
pantera1 [17]

Answer:

Explanation:

AVerage acceleration is the cjange in velocity with time

a = v-u/t

v is the final velocity = 48m/s

u is the initial velocity = 40m/s

t is the time = 6.5s

a = 48-40/6.5

a = 8/6.5

a = 1.23m/s²

Hence the magnitude of the car’s  average acceleration during this period is 1.23m/s²

4 0
3 years ago
A ship's propeller of diameter 3 m makes 10.6 revolutions in 30s. What is the angular velocity of the propeller?
ycow [4]

Answer:

The angular velocity of the propeller is 2.22 rad/s.

Explanation:

The angular velocity (ω) of the propeller is:  

\omega = \frac{\Delta \theta}{\Delta t}                              

Where:

θ: is the angular displacement = 10.6 revolutions

t: is the time = 30 s

\omega = \frac{\Delta \theta}{\Delta t} = \frac{10.6 rev*\frac{2\pi rad}{1 rev}}{30 s} = 2.22 rad/s

Therefore, the angular velocity of the propeller is 2.22 rad/s.

I hope it helps you!

5 0
3 years ago
Please help thank you
Margarita [4]

Answer:

\theta \approx 59.036^{\circ}, T_{2} \approx 23.324\,N

Explanation:

First we build the Free Body Diagram (please see first image for further details) associated with the mass, we notice that system consist of a three forces that form a right triangle (please see second image for further details): (i) The weight of the mass, (ii) two tensions.

The requested tension and angle can be found by the following trigonometrical and geometrical expressions:

\theta = \tan^{-1} \frac{W}{T_{2}} (1)

T_{1} = \sqrt{W^{2}+T_{2}^{2}} (2)

Where:

W - Weight of the mass, measured in newtons.

T_{1}, T_{2} - Tensions from the mass, measured in newtons.

If we know that W = 20\,N and T_{2} = 12\,N, then the requested values are, respectively:

\theta = \tan^{-1} \frac{20\,N}{12\,N}

\theta \approx 59.036^{\circ}

T_{2} = \sqrt{(20\,N)^{2}+(12\,N)^{2}}

T_{2} \approx 23.324\,N

7 0
3 years ago
3 kids are pushing on a cart 2 are pushing north at 50 N each. The 3rd is pushing South at -90 N. The net force is _N?
scoray [572]

Answer:

Explanation:

When two forces act in the same direction , they add up and when they act in opposite direction , they subtract .

2 forces each of 50 N act in same direction , so they will add up to give resultant force of 100 N . Now third force acts in opposite direction so 100 N and - 90 N will subtract to give total resultant force .

Resultant force = 100 - ( - 90 ) = 190 N

So net force or resultant force = 190 N .

6 0
3 years ago
Determine the magnitude of the resultant hydrostatic force acting on the dam and its location, measured from the top surface of
NemiM [27]

In your question a figure of dam is missing.where height is given which 6 m

Answer:

Force=1.41×10⁶ Newton

Location from surface of water= 4 m

Explanation:

Given Data

w (width)=8 m

p=1.0 Mg/m³

Force=?

Location=?

Solution

p=6(1)(10^{3} )(9.8)\\p=58860 \frac{N}{m^{2} }\\ Force=\frac{1}{2}(6)(8)(58,860)\\ F=1.41*10^{6}N\\ F=1.41MN\\h(location)=2/3(6)\\h=4m

8 0
4 years ago
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