Answer:
Explanation:
We know that there is a relation between the speed of light ,frequency and wavelength.This relation can be given as 
where v is speed of light 
is frequency of light 
is wavelength of light
In first case we have given λ=655 nm
so using formula
Hz
In second case we have wavelength 515 nm so by using above formula
In third case we have wavelength 475 nm
so 
(1) directed to the right
Explanation:
To the right of B, u(x) is a decreasing function & so its derivative is negative,this implies that the x component of the force on a particle at this position is positive,or that the force is directed towards right .Small deviations from equilibrium at point B causes a force to accelerate the particle away ,hence particle is in <u>unstable equilibrium.</u>
Answer:
a) 1.6*10^21 Joules.
b) 40,000
Explanation:
part a )
maximum destructive energy that can be released is the case when all the kinetic energy of the asteroid is consumed.
therefore E = 1/2 m v^2
m= density * volume
= 3100* (4/3* pi * 1000^3 ) = 12978666666666.67 kg
given v = 16000m/s
therefore
E= 1/2 * 12978666666666.67 * 16000 * 16000
= 1.6 x 10^21 Joules!
part B)
each bomb is capable of 4 x 10^16 joules
therefore no of bombs that are needed to produce the required energy are
1.6 x 10^21 / 4 x 10^16 = 40,000
that is 40,000 such nuclear bombs are required!
Answer:
The tension in the middle string is 3.3 N
Explanation:
Two boxes move with same acceleration
The tension in the middle string is T
Lets start with the forces acting in the 2nd box
→ The tension T in the string in the direction of motion
Due to Newtons's Law
→ ∑ Force in direction of motion = mass × acceleration
→ T = M a
→ M = 1 kg
Substitute the value of M is the equation
→ T = a ⇒ (1)
The force acting on the 1st box
→ The force F in the direction of motion, and T in the string in opposite
direction of motion
→ F - T = 2M a
→ F = 10 N , M = 1 kg
Substitute These values in the equation
→ 10 - T = 2(1) a
→ 10 - T = 2 a ⇒ (2)
Substitute equation (1) in (2)
→ 10 - T = 2 T
Add T to both sides
→ 10 = 3 T
Divide both sides by 3
→ T = 3.3 N
<em>The tension in the middle string is 3.3 N</em>
Answer:
(A) Fo = 72 Hz
(B) The pipe is open at both ends
(C) The length of the pipe is 2.38m
This problem involves the application of the knowledge of standing waves in pipes.
Explanation:
The full solution can be found in the attachment below.
For pipes open at both ends the frequency of the pipe is given by
F = nFo = nv/2L where n = 1, 2, 3, 4.....
For pipes closed at one end the frequency of the pipe is given by
F = nFo = nv/4L where n = 1, 3, 5, 7...
The full solution can be found in the attachment below.
