Complete Question 
 Due to blurring caused by atmospheric distortion, the best resolution that can be obtained by a normal, earth-based, visible-light telescope is about 0.3 arcsecond (there are 60 arcminutes in a degree and 60 arcseconds in an arcminute).Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light
Answer:
The diameter is   
     
Explanation:
 From the question we are told that 
       The best resolution is  
        The  wavelength is  
        
Generally the 
          1 arcminute  = >  60 arcseconds 
 =>      x arcminute =>   0.3 arcsecond 
So 
        
=>    
Now
          60 arcminutes  =>  1 degree 
           0.005 arcminutes = >  z degrees  
=>       
=>      
Converting to radian  
            
Generally the resolution is mathematically represented as 
             
=>    
=>      
     
=>      
     
 
        
             
        
        
        
Angle α between the velocity of theelectron and the magnetic field of the wire will be 90 degree
        
             
        
        
        
What are the following statements? If there's one that mention a description of current action, or motion, that's your answer.
        
             
        
        
        
Answer:
emf induced in the loop, at the instant when 9.0s have passed = 1.576 * 10 ⁻² V.
Direction is counter clockwise.
Explanation:
See attached pictures. 
 
        
             
        
        
        
Answer:
The gravitational acceleration of the planet is, g = 8 m/s²
Explanation:
Given data,
The distance the object falls, s = 144 m
The time taken by the object is, t = 6 s
Using the III equations of motion
                   S = ut + ½ gt²
∴                 g = 2S/t²
Substituting the given values,
                    g = 2 x 144 /6²
                       = 8 m/s² 
Hence, the gravitational acceleration of the planet is, g = 8 m/s²