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3 years ago

Convert 7.680 moles of PtSe to grams

Chemistry

1 answer:

puteri [66]3 years ago

7 0

Answer:

7.680 mol Pt Se aptse.

Convert 0.400 moles of BF3 to molecules.

0.400 mal BF3 x 6.02x 18 molecules BF3 = 2.4px 10.

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If 72.1 mL of 0.543 M H2SO4 completely titrates 39.0 mL of KOH solution, what is the molarity of the KOH solution? a. 0.317 M b.

Snezhnost [94]

Answer: The correct answer is Option d.

Explanation:

To calculate the molarity of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is KOH

We are given:

$n_1=2\\M_1=0.543M\\V_1=72.1mL\\n_2=1\\M_2=?M\\V_2=39.0mL$

Putting values in above equation, we get:

$2\times 0.543\times 72.1=1\times M_2\times 39.0\\\\M_2=2.01M$

Hence, the correct answer is Option d.

4 0

2 years ago

What type of bond exists between Na and N

Olegator [25]

Na is a metal

N is a nonmetal

thus, they form an ionic bond, where electrons are transferred from the metal, to the nonmetal

6 0

2 years ago

Phytoplankton are microscopic photosynthesizing organisms that typically live in the upper layers of the ocean. What trophic lev

alex41 [277]

Answer:

Primary producers

Explanation:

Phytoplankton belong to the primary producers trophic level. Beings of the other levels gain energy from phytoplankton. Phytoplankton are also capable of transforming inorganic carbon into protoplasm.

4 0

3 years ago

How are covelant and ionic bonds different and what types of elements combine to form each?

icang [17]

Answer:

Ionic bonds result from the transfer of electrons from one atom to another

Explanation:

In covalent bonds, atoms share electrons, whereas in ionic bonds atoms transfer electrons. The reaction components of covalent bonds are electrically neutral, whereas for ionic bonds they are both charged.Covalent bonds are formed between two non-metals, whereas ionic bonds are formed between a metal and non-metal.

7 0

2 years ago

Read 2 more answers

Calculate the freezing point of a solution 1.25 g benzene (C6H6) in 125 g of chloroform (CHCl3).

posledela

Answer:

The freezing point for the solution is -64.09°C

Explanation:

This problem can be solved, by the freezing point depression. This colligative problem shows, that the freezing point of a solution is lower than the freezing point of pure solvent.

ΔT = Kf. m

ΔT = T° freezing pure solvent - T° freezing solution

Kf = Cryscopic constant, for chloroform is 4.68

T°freezing pure solvent = -63.5°C

m is mol/kg of solvent → molality

Let's determine the moles of benzene

1.25 g / 78 g/mol = 0.0160 mol

Let's convert the mass of solvent to kg

125 g . 1kg / 1000 g = 0.125 kg

m = 0.0160 mol / 0.125 kg → 0.128 m

Let's go to the formula to replace the data

-63.5°C - T° freezing solution = 4.68 °C/m . 0.128 m

T° freezing solution = - (4.68 °C/m . 0.128 m + 63.5°C)

T° freezing solution = - 64.09°C

3 0

3 years ago