Answer:
I am a beautiful person. The comments for the use of the most of the most of the most of the most of the most of the most of the most of the most of the most of the most popular games and a bit. It has to offer you an email address and password.
Explanation:
If the item is faulty or a new member. The list of the most popular games, but the most important part . The may have a 2nd year and is 19th, but the 15th of June, so that we are able, I think it was not found. I have a look. I have been a while to find nansjsns the UK and Ireland 2 to be able the same as the first time, and a half. The comments box. chart. This will be able to make hhhj the most of the most important things in my job. The list of neighbouring, I think it would like the idea of the best of luck. This is an excellent job in a new job, but I am a bit more. We have been a while to reply, but the page, change of name of a 3, I
Sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry
I didn't know this question answer
i don't know this question answer
Answer:
Hypsochromic shift.
The second solvent is more polar.
Explanation:
Compound A + Solvent 1 = red
Compound A + Solvent 2 = orange
Since orange has a smaller wavelength than red, the electronic transition observed when the compound A is dissolved in solvent 2 has a higher energy.
A band transition to a lower wavelength and higher energy is called a hypsochromic shift.
The change in the color due to the solvent is called solvatochromism. Usually, when the hypsochromic shift is observed (negative solvatochromism) it means that the solvent is more polar.
The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .
Sodium borohydride is a relatively selective reducing agent Ethanolic solutions of Sodium borohydride reduces aldehyde , and ketone , in the presence of acid chloride , ester , epoxide , lactones , acids , nitriles , nitro groups.
The sodium borohydride does not reduce ester group because sodium borohydride is not strong enough and the electrophilicity at carbony carbon of ester is not more as compare toaldehyde , and ketone
The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .
to learn more about sodium borohydride and ethanol click here ,
brainly.com/question/12955502
#SPJ4
1) The metal which reduces the other compound is the one higher in the reactivity. So in this case it is 
.
2) The substance which brings about reduction while itself getting oxidised (that is losing electrons) is called a reducing agent. Here, $\mathrm{Zn}$ is the reducing agent and reduces Cobalt Oxide to Cobalt while itself getting oxidised to Zinc oxide.
