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4 years ago

13. How many valence electrons does an atom

Chemistry

1 answer:

Scilla [17]4 years ago

7 0

Answer:

The answer to your question is: 3

Explanation:

If an atom has 5 electrons, 5 neutrons and 5 protons, it means that the element is Boron. Boron is situated in the third group A, that means that is has 3 elements in its outermost shell.

Also, if we do the electronic configuration:

1s² 2s²2p¹

If we count the number of electron in the second level of energy, the result will be: 2 in s and 1 in p = 3. Those are the valence electrons.

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3 years ago

The reaction of Pb+4 and O-2 produces the compound of

vovikov84 [41]

Answer:

Pb₂O₄

Explanation:

The given species are:

Pb⁴⁺ O²⁻

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Pb⁴⁺ O²⁻

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3 years ago

If 100 ml of a 0.5 M HCI Solution is diluted with water to 1000ml, what is the new concetration?

Vesna [10]

Answer:

$0.05\ \text{M HCl}$

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$V_1$ = Initial volume = 100 mL

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$M_1$ = Initial concentration = 0.5 M

$M_2$ = Final concentration

We have the relation

$\dfrac{M_1}{M_2}=\dfrac{V_2}{V_1}\\\Rightarrow M_2=M_1\dfrac{V_1}{V_2}\\\Rightarrow M_2=0.5\times \dfrac{100}{1000}\\\Rightarrow M_2=0.05\ \text{M HCl}$

The new concentration is $0.05\ \text{M HCl}$ .

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3 years ago

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3 years ago

Read 2 more answers

Write the balanced nuclear equation for the following. (Use the lowest possible coefficients. Omit states-of-matter in your answ

olga55 [171]

Answer:

$_{93}^{232}\text{Np} + _{-1}^{0}\text{e} \longrightarrow _{92}^{232}\text{U}$

Explanation:

The unbalanced nuclear equation is

$_{93}^{232}\text{Np} + _{1}^{0}\text{e} \longrightarrow ?$

It is convenient to replace the question by an atomic symbol, $_{x}^{y}\text{Z}$ , where x = the atomic number, y = the mass number, and Z = the symbol of the element.

$_{93}^{232}\text{Np} + _{1}^{0}\text{e} \longrightarrow _{x}^{y}\text{Z}$

Then your equation becomes

$_{93}^{232}\text{Np} + _{1}^{0}\text{e} \longrightarrow _{x}^{y}\text{Z}$

The main point to remember in balancing nuclear equations is that the sums of the superscripts and of the subscripts must be the same on each side of the equation.

Then

93 – 1 = x, so x = 92

232 + 0 = y, so y = 232

Element 92 is uranium, so the nuclear equation becomes

$_{93}^{232}\text{Np} + _{-1}^{0}\text{e} \longrightarrow _{92}^{232}\text{U}$

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3 years ago