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bearhunter [10]
3 years ago
6

Arrange these elements based on their atomic radii. ga, f, s, as

Chemistry
1 answer:
mamaluj [8]3 years ago
5 0

please have look at Periodic table , you will solve it yourself !

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If antique brass is 30.0% zinc and 70.0% copper, how many grams of antique brass can be made from 18.0 grams of zinc and 32.8 gr
wariber [46]

Answer: 51.86

Explanation:

3 0
3 years ago
Atomic Structure of 14 Elements Please use the periodic table of elements to answer the questions below. How can you determine t
andrew-mc [135]

Silicon has 14 protons Potassium has 19 electrons The neutrons are equal to the mass number minus the atomic number. Or the big number minus the small number on the periodic table. hydrogen 1 does not have a neutron.

iron =56 -26 for 30 neutrons in the nucleus

Chlorine 17 protons and 17 electrons. 18 or 19 neutrons on average.

7 0
3 years ago
Read 2 more answers
How many moles of sodium hydroxide would react with 1 Mole of sulphuric acid?
Paul [167]

Answer:

Two moles.

Explanation:

Sulphuric (sulfuric) acid \rm H_2SO_4 is a diprotic acid. When one mole of \rm H_2SO_4 molecules dissolve in water, two moles of \rm H^{+} ions would be produced.

\rm H_2SO_4 \to 2\, H^{+} + {SO_4}^{2-}.

On the other hand, sodium hydroxide \rm NaOH is a monoprotic base. When one mole of \rm NaOH formula units dissolve in water, only one mole of hydroxide ions \rm OH^{-} would be produced.

\rm NaOH \to Na^{+} + OH^{-}.

Note that \rm H^{+} and \rm OH^{-} react at a one-to-one ratio:

\rm H^{+} + OH^{-} \to H_2O.

As a result, it would take 2\; \rm mol of \rm OH^{-} to react with the \rm 2\; mol of \rm H^{+} that was released when 1\; \rm mol of \rm H_2SO_4 is dissolved in water. Since one mole of \rm NaOH formula units could produce only one mole of \rm OH^{-}, it would take \rm 2\; mol of \rm NaOH formula units to produce that 2\; \rm mol of \rm OH^{-} for reacting with 1\; \rm mol of \rm H_2SO_4.

3 0
3 years ago
Tara predicts the number of paper clips attracted by the magnet
muminat

The responding variable refers to the variable that changes as the independent variable is being manipulated. In this case, the responding variable is the number of paper clips attracted by the magnet.

An experiment must include a dependent (responding) variable and an independent variable. As the independent variable is manipulated during the experiment, the dependent (responding) variable changes accordingly.

In this case; the independent variable is temperature while the dependent (responding) variable is the number of paper clips attracted by the magnet.

Learn more: brainly.com/question/967776

7 0
3 years ago
How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with
konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = a=31 cm^2

Thickness of the gold plating  = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3

Density of the gold = d=19.3 g/cm^3

m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g

Moles of gold = \frac{29.915 g}{197 g/mol}=0.152 mol

Au^{3+}+3e^-\rightarrow Au

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

\frac{3}{1}\times 0.152 mol=0.456 mol of electrons

Number of electrons = N =0.456\times \times 6.022\times 10^{23}

Charge on single electron = q=1.6\times 10^{-19} C

Total charge required = Q

Q=N\times q

Amount of current passes = I = 8 Ampere

Duration of time  = T

I=\frac{Q}{T}

T=\frac{N\times q}{I}

=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

7 0
3 years ago
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