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bearhunter [10]
3 years ago
6

Arrange these elements based on their atomic radii. ga, f, s, as

Chemistry
1 answer:
mamaluj [8]3 years ago
5 0

please have look at Periodic table , you will solve it yourself !

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What is the term for the number of protons in the nucleus of each atom of an element?
xxTIMURxx [149]

Answer:

atomic number

Explanation:

atomic number is the number of protons

5 0
2 years ago
If m = 45g and V = 15ml, what is D in g/ml?​
ch4aika [34]

Answer:

3 g/mL

Explanation:

We know that the density of an object can be measured by dividing its mass (g) to its volume (mL).

Formula

D=m/v

Given data:

Mass= 45 g

Volume= 15 mL

Now we will put the values in formula:

D=45 g/ 15 mL= 3 g/mL

6 0
3 years ago
Which of the following statements about the carbon cycle is NOT true?
nalin [4]

Answer:

Plants consume carbon through transpiration

Explanation:

In transpiration, plants lose water vapor through the stomata in their leaves. No carbon is involved in transpiration, which has an outbound direction. Nothing can be consumed through the stomata when vapor is going out of the plant. It´s like trying to get in through the exit.

3 0
3 years ago
Read 2 more answers
Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that
iragen [17]

Answer:

108.43 grams KNO₃

Explanation:

To solve this problem we use the formula:

  • ΔT = Kf * b * i

Where

  • ΔT is the temperature difference (14.5 K)
  • Kf is the cryoscopic constant (1.86 K·m⁻¹)
  • b is the molality of the solution (moles KNO₃ per kg of water)
  • and<em> i</em> is the van't Hoff factor (2 for KNO₃)

We <u>solve for b</u>:

  • 14.5 K = 1.86 K·m⁻¹ * b * 2
  • b = 3.90 m

Using the given volume of water and its density (aprx. 1 g/mL) we <u>calculate the necessary moles of KNO₃</u>:

  • 275 mL water ≅ 275 g water
  • 275 g /1000 = 0.275 kg
  • moles KNO₃ = molality * kg water = 3.90 * 0.275
  • moles KNO₃ = 1.0725 moles KNO₃

Finally we <u>convert KNO₃ moles to grams</u>, using its molecular weight:

  • 1.0725 moles KNO₃ * 101.103 g/mol = 108.43 grams KNO₃
5 0
2 years ago
A 0.15 m solution of chloroacetic acid has a ph of 1.86. What is the value of ka for this acid?
dem82 [27]

Answer: 1.67\times 10^{-3}

Explanation:

ClCH_2COOH\rightarrow ClCH_2COO^-+H^+

   cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Given:  c = 0.15 M

pH = 1.86

K_a = ?

Putting in the values we get:

Also pH=-log[H^+]

1.86=-log[H^+]

[H^+]=0.01

[H^+]=c\times \alpha

0.01=0.15\times \alpha

\alpha=0.06

As [H^+]=[ClCH_2COO^-]=0.01

K_a=\frac{(0.01)^2}{(0.15-0.15\times 0.06)}

K_a=1.67\times 10^{-3]

Thus the vale of K_a for the acid is 1.67\times 10^{-3}

4 0
3 years ago
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