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3 years ago

How cold is it on Uranus

Chemistry

1 answer:

Sav [38]3 years ago

6 0

Answer:

-371 degrees f

Explanation:

-371 degrees F.

speeds on Uranus range from 90 to 360 mph and the planet's average temperature is a frigid -353 degrees F. The coldest temperature found in Uranus' lower atmosphere so far is -371 degrees F., which rivals Neptune's frigid temperatures.

(hope this helps can i plz have brainlist :D hehe)

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Which of the following are products of combustion?

Galina-37 [17]

The answer option which are products of combustion is: D. Heat and light.

In Chemistry, there are five (5) main types of chemical reaction and these include;

Combination reaction.

Double-replacement reaction.

Decomposition reaction.

Single-replacement reaction.

Combustion reaction.

A combustion reaction can be defined as an exothermic chemical reaction between physical substances, usually in the presence of oxygen and hydrocarbons to produce heat, light and carbon.

An example of a combustion reaction is the burning of forest trees and plants.

In conclusion, the products of combustion are heat and light.

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3 years ago

The potential energy diagram for a reaction starts at 180 kJ and ends at 300 kJ. What type of reaction does the diagram best rep

quester [9]

Answer: Endothermic reaction

Explanation:

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and $\Delta H$ for the reaction comes out to be negative.

Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and $\Delta H$ for the reaction comes out to be positive.

As the energy of reactants is 180 kJ and that of products is 300 kJ, the energy of products is greater than that of reactants, which means the energy has been absorbed and reaction is endothermic.

4 0

4 years ago

What is the temperature, in degrees Celsius, of a substance with a temperature of 49K? –322°C –224°C 224°C 322°C

vichka [17]

Answer:

-224ºC

Explanation:

4 0

3 years ago

A closed vessel system of volume 2.5 L contains a mixture of neon and fluorine. The total pressure is 3.32 atm at 0.0°C. When th

Oxana [17]

Answer: moles of Ne = 0.149 moles

moles of F₂ = 0.221 moles

Explanation:

The process occurs at costant volume.

Neon is a monoatomic gas, Cv =3/2R, Flourine is a diatomic gas, Cv = 5/2R

n = PV/RT ; where n is total = number of moles, P is total pressure = 3.32atm, V is volume = 2.5L, R is molar gas constant = 0.08206 L-atm/mol/K = 8.314 J/mol/K, T is temperature = 0.0°C = 273.15K

n(total) = (3.32 atm)(2.5 L)/(0.08206 L-atm/mol/K)(273.15) = 0.3703 mol

For one mole heated at constant volume,

Change in entropy, ∆S = ∫dq/T = ∫(Cv/T)dT

From T1 to T2, Cvln(T2/T2) = Cvln(288.15/273.15) = 0.05346•Cv

So, for 0.3703 moles,

∆S = (0.3703 mol)(0.05346)Cv = 0.345 J/K

⇒ Cv = 17.43 J/mol/K for the Ne/F₂ mixture.

For pure Ne, Cv = (3/2)R = 1.5 • 8.314 J/mol/K = 12.471 J/mol/K

For pure F₂, Cv = (5/2)R = 2.5 • 8.314 J/mol/K = 20.785 J/mol/K

If Y is the mole fraction of Ne, Y can be determined by setting the observed entropy change (∆S) to the weighted average of the entropy changes expected for the two different gases in the mixture:

17.43 J/mol/K = Y * 12.471 J/mol/K + (1 – Y) * 20.785 J/mol/K

⇒ 20.785 J/mol/K – 8.314 J/mol/K * Y = 17.43J/mol/K

Y = 0.403 ; 1 – Y = 0.597

moles of Ne = (0.403)(0.3703 mol) = 0.149 moles

moles of F₂ = (0.597)(0.3703 mol) = 0.221 moles

7 0

3 years ago

What reaction is a reaction in which energy is absorbed

Papessa [141]

Answer: endothermic

Explanation: Endothermic Reactions. A system of reactants that absorbs heat from the surroundings in an endothermic reaction has a positive (H), because the enthalpy of the products is higher than the enthalpy of the reactants of the system.

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2 years ago