Answer: 2.5°C
Explanation:
Initial volume V1 = 5.38 liters
Initial temperature T1 = 36.0°C
Convert temperature in Celsius to Kelvin
(32°C + 273= 305K)
Final temperature T2 = ?
Final volume V2 = 4.68 liters
According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.
Thus, Charles' Law is expressed as: V1/T1 = V2/T2
5.38/305 = 4.86/T2
To get the value of T2, cross multiply
5.38 x T2 = 4.86 x 305
5.38T2 = 1482.3
Divide both sides by 5.38
5.38T2/5.38 = 1482.3/5.38
T2 = 275.5K
Convert 275.5K to Celsius
(275.5K - 273K = 2.5°C)
Thus, the final temperature is 2.5°C
Answer:
The ratio of HC2H3O2(aq) in the flask after the addition of 5.0mL of NaOH(aq) to HC2H3O2(aq) in the flask after the addition of 1.0mL of NaOH(aq) is 15 : 19 .
Explanation:
HC2H3O2 is CH₃⁻ COOH, which is also known as Acetic acid.
IUPAC name of this compound is Ethanoic acid.
Acetic acid has a basicity of 1. so there is one acidic hydrogen is acetic acid.
Given that, equivalence point was reached when 20.0mL of NaOH is added.
let the normality of acetic acid is N₁ and that of NaOH is N₂.
volume of acetic acid is V₁ and that of NaOH is V₂.
Equivalence point occurs when, N₁ × V₁ = N₂ × V₂.
⇒ N₁ × V₁ = N₂ × 20.
after the addition of 5.0mL of NaOH(aq), remaining N₁ × V° = N₂ × (20 - 5).
= N₂ × 15.
after the addition of 1.0mL of NaOH(aq), remaining N₁ × Vˣ = N₂ × (20 - 1).
= N₂ × 19.
⇒ V° : Vˣ = 15 : 19 .
⇒
the correct answer to this question is C
To determine the mass of the sample in milligrams in this problem, we use the avogadro's number to convert from atoms to moles, relate the moles of element in the sample to the mole present and the molar mass of the sample. We do as follows:
1.552 x 10^22 atoms H ( 1 mol H / 6.022x10^23 atoms H ) ( 1 mol C2H4Cl2 / 4 mol H ) ( 98.96 g C2H4Cl2 / 1 mol C2H4Cl2 ) = 0.625 g C2H4Cl2 = 625 mg <span>C2H4Cl2</span>
Answer:
No it is not balanced
Explanation:
CaCl2 + 2NaHCO3 → CO2 + CaCO3 + H2O + 2NaCl
Hope this helps
