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labwork [276]
3 years ago
10

1What is one major difference between fossil fuels and biofuels?

Chemistry
1 answer:
Margarita [4]3 years ago
4 0
The correct answer is A
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To show the electron configuration for an atom, what is the advantage of using an orbital notation compared to a dot structure?
stich3 [128]
The advantage of using an orbital notation is that it shows the electron distribution in shells. 

<span>Dot structures only show the valence electrons of an atom which are the electrons found at the outermost shell. The orbital notation gives a more detailed depiction of the electrons in each shell. This is most advantageous for atoms that have special cases. </span>

<span>Some examples of atoms that have special electronic configurations are copper and chromium. For example, copper is more stable when the 3d subshell is completely filled. This leaves the 4s subshell with only 1 electron. Chromium is also more stable when its s and d subshells are only half full. The orbital notation depicts these special cases, whereas the dot structure does not.</span>
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3 years ago
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What is the name of the change when a liquid becomes a solid?​
Tcecarenko [31]

Answer:

solidification

And when a solid turn into liquid it's liquidation

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How does the nicotine and tar content of sidestream smoke compare to that of mainstream smoke
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Details please.

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6 0
4 years ago
A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som
irinina [24]

Answer:

m_{KBr}=6.030gKBr

Explanation:

Hello.

In this case, since the normal boiling point of X is 117.80 °C, the boiling point elevation constant is 1.48 °C*kg*mol⁻¹, the mass of X is 100 g and the boiling point of the mixture of X and KBr boils at 119.3 °C, we can use the following formula:

(T_b-T_b_0)=i*m*K_b

Whereas the Van't Hoff factor of KBr is 2 as it dissociates into potassium cations and bromide ions; it means that we can compute the molality of the solution:

m=\frac{T_b-T_b_0}{i*K_b}=\frac{(119.3-117.8)\°C}{2*1.48\°C*kg*mol^{-1}}\\  \\m=0.507mol/kg

Next, given the mass of solventin kg (0.1 kg from 100 g), we compute the moles KBr:

n_{KBr}=0.507mol/kg*0.1kg=0.0507mol

Finally, considering the molar mass of KBr (119 g/mol) we compute the mass that was dissolved:

m_{KBr}=0.0507mol*\frac{119g}{1mol} \\\\m_{KBr}=6.030gKBr

Best regards.

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4 years ago
What happens to the pressure and the molecules inside a unicycle tire that is being pumped up?
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B. The pressure increases, and the molecules collide with the tire’s inner surface.
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