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Veseljchak [2.6K]
3 years ago
13

The d subshell can hold up to 10 electrons in an atom. True False

Chemistry
2 answers:
nevsk [136]3 years ago
7 0
False, im pretty sure you can fit way more electrons in an atom 
iris [78.8K]3 years ago
5 0

Answer:

TRUE

Explanation:

Each electronic shell in an atom is composed of subshells, which are denoted by the symbol s, p, d and f. These subshells are represented by the principal quantum number (n) and the azimuthal quantum number (ℓ).  

Each subshell can hold a fixed number of electrons, which is equal to (4ℓ + 2) electrons.

For, d subshell the value of ℓ = 2.

<u>Therefore, the maximum number of electrons that a d-orbital can hold = (4ℓ + 2) electrons = (4×2 + 2) electrons = 10 electrons.</u>

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What are the relationships between temperature and viscosity of water?
iris [78.8K]

Explanation:

Both cohesion and molecular interchange contribute to liquid viscosity. The impact of increasing the temperature of a liquid is to reduce the cohesive forces while simultaneously increasing the rate of molecular interchange. The former effect causes a decrease in the shear stress while the latter causes it to increase.

temperature?

The viscosity of liquids decreases rapidly with an increase in temperature, and the viscosity of gases increases with an increase in temperature. Thus, upon heating, liquids flow more easily, whereas gases flow more sluggishly.

mark as brainliest

8 0
3 years ago
A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.692 kg of water
S_A_V [24]

Answer:

494.49 g of NaCl.

Explanation:

Data obtained from the question include the following:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mass of NaCl =.?

Next, we shall determine the number of mole of NaCl in the solution.

Molality is simply defined as the mole of solute per unit kilogram of solvent. Mathematically, it is expressed as

Molality = mole of solute /Kg of solvent

With the above formula, we can obtain the number of mole NaCl in the solution as follow:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mole of NaCl =..?

Molality = mole of solute /Kg of solvent

3.140 = mole of NaCl /2.692

Cross multiply

Mole of NaCl = 3.140 x 2.692

Mole of NaCl = 8.45288 moles

Finally, we shall covert 8.45288 moles of NaCl to grams. This can be obtained as follow:

Mole of NaCl = 8.45288 moles

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =.?

Mole = mass /Molar mass

8.45288 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 8.45288 × 58.5

Mass of NaCl = 494.49 g.

Therefore, 494.49 g of NaCl are present in the solution.

8 0
3 years ago
Please help :) ill mark you as the brainiest hope you have a good day
Hitman42 [59]

Have a wonderful day :) thanks for the points

5 0
3 years ago
How do I calculate the molecular weight of Mg(OH)2?
vodomira [7]

The molecular weight of Mg(OH)2 : 58 g/mol

<h3>Further explanation</h3>

Given

Mg(OH)2 compound

Required

The molecular weight

Solution

Relative atomic mass (Ar) of element : the average atomic mass of its isotopes  

Relative molecular weight (M)  : The sum of the relative atomic mass of Ar  

M AxBy = (x.Ar A + y. Ar B)  

So for Mg(OH)2 :

= Ar Mg + 2 x Ar O + 2 x Ar H

= 24 g/mol + 2 x 16 g/mol + 2 x 1 g/mol

= 24 + 32 + 2

= 58 g/mol

5 0
3 years ago
Consider the electrolysis of aqueous agno3. Refer to the table of standard reduction potentials as needed. What should form at t
Valentin [98]

Answer:

Ag+

Explanation:

anode: 2AgNO3(l)⟶Ag(aq)+NO3(g)

8 0
3 years ago
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