Answer:
T₂ = 859.4 K
Explanation:
Given data:
Initial volume of gas = 32.0 L
Initial temperature = 2°C (2 + 273 = 275 k)
Final temperature = ?
Final volume = 1.00 ×10²L
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁ /V₁
T₂ = 1.00 ×10²L × 275 K / 32.0 L
T₂ = 27500 L.K / 32.0 L
T₂ = 859.4 K
Answer:
2.60 g of H₂ and 20.8 g of O₂ are produced in the decomposition of 23.44 g of water
Explanation:
Water decomposition is:
2H₂O → 2H₂ + O₂
We convert the mass of water, to moles:
23.44 g . 1 mol/18 g = 1.30 moles
Ratio is 2:2 with hydrogen and 2:1 with oxygen. Let's make rules of three:
2 moles of water can produce 2 moles of hydrogen gas and oxygen gas
Then, 1.30 moles will produce:
(1.30 . 2) /2 = 1.30 moles of H₂
(1.30 . 1) /2 = 0.65 moles of O₂
We convert the moles to mass
1.30 moles of H₂ . 2g / 1mol = 2.60 g of H₂
0.65 moles of O₂ . 32 g / 1 mol = 20.8 g of O₂
<span>Waste products in the cell accumulate and are eventually moved out of the cell and eliminated.
Given that these products are waste, and can be harmful to the organism, they need to be eradicated, and thrown out of the system.
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