Recently a local government has observed that the number of people suffering from respiratory diseases has increased. What measu
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Answer : When we increase the temperature of an exothermic reaction the equilibrium will shift to the left direction i.e, towards the reactant.
Explanation :
Le-Chatelier's principle : This principle states that if any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
As the given reaction is an exothermic reaction in which the heat is released during a chemical reaction. That means the temperature is decreased on the reactant side.
For an exothermic reaction, heat is released during a chemical reaction and is written on the product side.
If the temperature is increases in the equilibrium then the equilibrium will shift in the direction where, temperature is getting decreased. Thus, the reaction will shift to the left direction i.e, towards the reactant.
Hence, when we increase the temperature of an exothermic reaction the equilibrium will shift to the left direction i.e, towards the reactant.
Question 7.
Given:
Mass, m = 2200 kg
Time, t = 8 s
Velocity = 12 m/s
Let's find the average net force required to stop the car.
To find the average net force required to stop the car, let's first find the acceleration of the car.
Where:
Initial velocity, vo = 12 m/s
Final velocity, v = 0 m/s (velocity of car when it stops)
t is the time = 8 seconds
a is the acceleration.
Rewrite the formula for a:
Hence, we have:
The acceleration is -1.5 m/s² (negative because the car is deccelerating).
Now, to find the net force, we have:
Where:
m is the mass = 2200 kg
a is the acceleration = -1.5 m/s²
Hence, we have:
The negative sign indicates that the force acts in the opposite direction the car is travelling.
Therefore, average net force required to stop the car is 3300 Newtons in the opposite direction.
ANSWER:
3300 N in the opposite direction
Answer:
The separation between the first two minima on either side is 0.63 degrees.
Explanation:
A diffraction experiment consists on passing monochromatic light trough a small single slit, at some distance a light diffraction pattern is projected on a screen. The diffraction pattern consists on intercalated dark and bright fringes that are symmetric respect the center of the screen, the angular positions of the dark fringes θn can be find using the equation:
with a the width of the slit, n the number of the minimum and λ the wavelength of the incident light. We should find the position of the n=1 and n=2 minima above the central maximum because symmetry the angular positions of n=-1 and n=-2 that are the angular position of the minima below the central maximum, then:
for the first minimum
solving for θ1:
for the second minimum:
So, the angular separation between them is the rest: