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julia-pushkina [17]
3 years ago
13

hi:) anyone able to explain no.2 of what happens to particles of a solid that is heated until it melts? I don’t understand it. T

hanks !

Chemistry
1 answer:
Viefleur [7K]3 years ago
8 0
In a solid the particles are all really close together and stuck like that. As the solid melts and becomes a liquid the particles spread out. A solid won’t easily change its shape because the particles are bound together but in a liquid the shape is more fluid, take water when you pour it into a container it will change to fit the shape of a container this is because the particles aren’t as close and can move around. The particles of a solid change when it melts because it is changing states to a liquid.
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blsea [12.9K]

The statement<em> "it is not the union that organizes the employees; it is management "</em> means that :

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2 years ago
What is the definition of a common ion as it applies to Le Chatelier’s principle?
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The definition of a common ion as it applies to Le Chatelier's principle is an ion that is present in an equilibrium system and a compound added to the system. This is the case since in Le Chatelier's principle, it is based on an equilibrium system and where the reaction shifts to the left or to the right; towards the products or the reactants side.  
6 0
3 years ago
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Please help asap!!!!
djyliett [7]
B is the answer..!
Disturbance is in a circular motion
7 0
3 years ago
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If 5g of H2 are reacted with excess CO, how many grams of CH3OH are produced, based on a yield of 86%?
Cerrena [4.2K]

Answer: 34.4 g

Explanation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of hydrogen}=\frac{5g}{2g/mol}=2.5moles

As CO is in excess, H_2 is the limiting reagent and thus it will limit the formation of products.

CO+2H_2\rightarrow CH_3OH

According to stoichiometry:

2 moles of hydrogen produce = 1 mole of CH_3OH

2.5 moles of hydrogen produce = \frac{1}{2}\times 2.5=1.25 moles of CH_3OH

Mass of CH_3OH=moles\times {\text {Molar mass}}=1.25\times 32=40g

But as % yield is 86%, mass of CH_3OH produded is \frac{86}{100}\times 40=34.4g

Thus 34.4 g of CH_3OH is produced.

6 0
3 years ago
6 NaOH + 2 Al ???? 2 Na3AlO3 + 3 H2 How much aluminum is required to produce 17.5 grams of hydrogen? How many moles of NaOH are
ANTONII [103]

Answer:

a) 157.5 grams of aluminum.

b) 1 mol

c) 9 g

Explanation:

The reaction is :

6 NaOH + 2Al ---> 2 Na_{3}AlO_{3} + 3H_{2}

As per balanced equation

a) 3 moles of hydrogen will be produced from two moles of aluminium.

The atomic mass of aluminium = 27

therefore

3X2 grams of hydrogen is produced from 2 X 27 grams of Al

1 gram of hydrogen will be produced from \frac{2X27}{3X2}= 9g

therefore 17.5 will be produced from = 9X 17.5 = 157.5 grams of aluminum.

b) as per balanced equation three moles or six gram of hydrogen is produced from 6 moles of NaOH.

Therefore 1 g of hydrogen will be produced from =\frac{6}{6}

or 1 gram will be prepared from = 1 mole

c) from balanced equation three moles are produced from two moles of Al (27X2 = 54 g).

thus from 54  grams gives 6 grams of hydrogen

1 grams will give = \frac{54X1}{6}= 9 g

7 0
3 years ago
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