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bearhunter [10]
2 years ago
6

A burning match will burn more vigorously in pure oxygen than in air because _________ . Select one: a. oxygen is a catalyst for

combustion b. nitrogen is a reactant in combustion and its low concentration in pure oxygen catalyzes the combustion c. oxygen is a product of combustion d. nitrogen is a product of combustion and the system reaches equilibrium at a lower temperature e. oxygen is a reactant in combustion and pure oxygen increases the reactant concentration
Chemistry
1 answer:
Westkost [7]2 years ago
8 0

Answer:

e. oxygen is a reactant in combustion and pure oxygen increases the reactant concentration

Explanation:

The reaction of a burning match is combustion. In this combustion, the organic components of the match (such as cellulose, C₆H₁₀O₅) react with oxygen, producing water and carbon dioxide:

  • C₆H₁₀O₅(s) + 6O₂(g) → 5H₂O(g) + 6CO₂(g)

Seeing as oxygen is a reactant and not a catalyst nor product, and that nitrogen plays no part in the reaction, <em>the only correct answer is option e</em>.

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What mass of iron would be required to react with 10.0L of O2 gas?
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33.2 g of iron (Fe)

Explanation:

We have the following chemical reaction in which iron react with oxygen to form the iron (III) oxide:

4 Fe + 3 O₂ → 2 Fe₂O₃

number of moles = volume / 22.4 (L/mole)

number of moles of O₂ = 10 / 22.4

number of moles of O₂ = 0.446 moles

Taking in account the chemical reaction we devise the following reasoning:

if           4 moles of Fe react with 3 moles of O₂

then     X moles of Fe react with 0.446 moles of O₂

X = (4 × 0.446) / 3 = 0.595 moles of Fe

number of moles = mass / molar weight

mass =  number of moles × molar weight

mass of Fe = 0.595 × 55.8

mass of Fe = 33.2 g

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number of moles

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